The Java interface doesn't declare any exception. How to manage checked exceptions of the implementation?

问题

Let's say I have the following Java interface that I may not modify:

public interface MyInterface {
  public void doSomething();
}

And now the class implementing it is like this:

class MyImplementation implements MyInterface {
  public void doSomething() {
    try {
      // read file
    } catch (IOException e) {
      // what to do?
    }
  }
}

I can't recover from not reading the file.

A subclass of RuntimeException can clearly help me, but I'm not sure if it's the right thing to do: the problem is that that exception would then not be documented in the class and a user of the class would possibly get that exception an know nothing about solving this.

What can I do?

We all agree: the interface is faulty.

Solution I chose

I finally decided to write a MyVeryOwnInterface that extends MyInterface and adds as part of the signature of the faulty methods the MyRuntimeException:

public interface MyVeryOwnInterface extends MyInterface {
  public void doSomething() throws MyRuntimeException;
}
class MyImplementation implements MyVeryOwnInterface {
  public void doSomething() throws MyRuntimeException {
    try {
      // read file
    } catch (IOException e) {
      throw new MyRuntimeException("Could not read the file", e);
    }
  }
}

回答1:

You've encountered the problem of leaky abstractions. There is no really good solution, and using a RuntimeException pretty much the only thing you can do.

Arguably, this is also an example for why checked exceptions are a failed concept.

回答2:

I'd throw a new IOError(e); and file an issue at the maintainer of the interface.

回答3:

If you can't recover than you need to throw and thus wrap it into a RuntimeException or an Error and throw that.

public class Unchecked extends Error {

   private final Exception source;

   public Unchecked( Exception source) {
       this.source = source;
   }

   public String toString() {
       return "Unchecked Exception, Caused by: " + source;
   }

   public Exception getSource() {
       return source;
   }

   public static Unchecked wrap( Exception cause ) {
       return new Unchecked(cause);
   }
}

回答4:

Clearly the interface designer is at fault for not considering the possibility that doSomething() may fail. Ideally he should have either allowed IOException to be thrown (if he suspected that IO wouldbe invovled) or a SomethingException (checked) which you could use to wrap your IOException.

If the interface designer is available to you, talk to them and ask what they expected to happen in the case of failure. Maybe they can change the interface: or maybe it is acceptable to fail silently according to the interface's contract.

Failing all of these you are reduced to a choice of failing silently (possibly recording but not responding to the problem) or throwing a RuntimeException which may terminate the process.

回答5:

I don't think there is anything to do except to declare throws IOException in the interface. That is simply the nature of Java interfaces and checked exceptions.

You could have another method in your class (doSomethingDangerous) that throws the IOException. From the doSomething-implementation, you simply call doSomethingDangerous (wrapped in a try/catch) and then where ever you wish to be careful about doingSomething you call doSomethingDangerous directly.

回答6:

I would suggest

throw new RuntimeException("while reading file " + fileName + "...", e);

Isn't the problem here, that the interface does not expect any problems at all?

(and you may want to create your own OurCompanyDomainException extends RuntimeException to make it easy to distinguish in the code on the other side of the interface).

来源：https://stackoverflow.com/questions/2738827/the-java-interface-doesnt-declare-any-exception-how-to-manage-checked-exceptio

标签

java

exception-handling

interface