问题
preamble: a few days ago I asked a question to solve a HABTM-filter, I'm not able to do it even with tutorials, so "Obi Kwan Kenobi youre my only hope".
What I want to achieve: Filtering Staff by GroupID which is used in StaffStaffgroup
I'm having the following tablelayout
- staffs (a person can belong to many groups)
- staff_staffgroups (HABTM-linking table)
- staffgroups (has a groupname)
The variable $tmp gets me a working array, but the problem is that Staff is a child object of StaffStaffgroups. I could parse throu and reassemble a array, but this isnt a nice solution. So I want to use the condition on Staff (see comented line) but then I get the error 1054 "column not found: 1054 Unknown column". I tried to bind and unbind, but no result there.
$group_id = 2;
$tmp = $this->Staff->StaffStaffgroup->find('all',
array('conditions' => array(
'StaffStaffgroup.staffgroup_id' => $group_id,
'Staff.isActive =' => "1",
'Staff.last_name LIKE' => "%$name%",
)
)
);
debug($tmp);
//$tmpConditions['AND'][] = array('StaffStaffgroup.staffgroup_id' => $group_ids);
EDIT:
I tried it with conditions and containable behaviour, but unfortunatelly its not filtering anything at all
$this->Staff->contain(array('StaffStaffgroup'));
$this->paginate = array('StaffStaffgroup' =>array(
array('conditions' => array(
'StaffStaffgroup.staffgroup_id' => '2'
)
)
)
);
- I added to all models: public $actsAs = array('Containable');
I tried also with an inner join but no filtering there:
$this->paginate = array( 'conditions' => array('StaffStaffgroup.staffgroup_id' => 2 ), 'joins' => array( array( 'alias' => 'StaffStaffgroup', 'table' => 'staff_staffgroups', 'type' => 'INNER', 'conditions' => 'StaffGroup_id = StaffStaffgroup.staffgroup_id' ) )
);
回答1:
You cannot use the Containable behavior for this. Checkout the sql dump, you will see that the query is done.
I would do it in two steps
From StaffStaffgroup get the staff ids that belongs to the group you want
$staff_ids = $this->Staff->StaffStaffgroup->find(
'all',
array(
'conditions' => array('StaffStaffgroup.staffgroup_id' => $group_id, ),
'recursive' => -1,
'fields' => array('StaffStaffgroup.staff_id'),
)
);
Then get all staff using the previous result
$staffs = $this->Staff->find(
'all',
array(
'conditions' => array(
'Staff.id' => $staff_ids,
'Staff.isActive =' => "1",
'Staff.last_name LIKE' => "%$name%",
),
)
);
回答2:
You should look into the Containable behaviour.
http://book.cakephp.org/2.0/en/core-libraries/behaviors/containable.html
This will allow you to query your Staff model and contain your StaffStaffgroup model, giving you the array organised in the way you want.
回答3:
I realize this question was asked a long time ago but my comment could still help someone else finding this post.
I created a behavior that creates the proper joins to the HABTM association behind the scenes making you able to use conditions on the HABTM-model.
Example
The model:
<?php
class Product extends AppModel {
public $actsAs = array(
'FilterHabtm.FilterHabtm',
'Containable' // If you use containable it's very important to load it AFTER FilterHabtm
);
public $hasAndBelongsToMany = array(
'Category' => array(
'className' => 'Category',
'foreignKey' => 'product_id',
'associationForeignKey' => 'category_id',
'with' => 'CategoryProduct'
)
);
}
The controller:
(The following is made possible by the behavior)
<?php
class ProductsController extends AppController {
public $name = 'Products';
public function index($categoryId = null) {
$products = $this->Product->find('all', array(
'conditions' => array(
'Category.id' => $categoryId // Filter by HABTM conditions
)
));
}
}
Please see this url for download and complete usage instructions: https://github.com/biesbjerg/FilterHabtm
来源:https://stackoverflow.com/questions/14691452/filter-habtm-associated-model-with-conditions