Selecting last element in JavaScript array [duplicate]

时光总嘲笑我的痴心妄想 提交于 2019-11-26 23:25:28

How to access last element of an array

It looks like that:

var my_array = /* some array here */;
var last_element = my_array[my_array.length - 1];

Which in your case looks like this:

var array1 = loc['f096012e-2497-485d-8adb-7ec0b9352c52'];
var last_element = array1[array1.length - 1];

or, in longer version, without creating new variables:

loc['f096012e-2497-485d-8adb-7ec0b9352c52'][loc['f096012e-2497-485d-8adb-7ec0b9352c52'].length - 1];

How to add a method for getting it simpler

If you are a fan for creating functions/shortcuts to fulfill such tasks, the following code:

if (!Array.prototype.last){
    Array.prototype.last = function(){
        return this[this.length - 1];
    };
};

will allow you to get the last element of an array by invoking array's last() method, in your case eg.:

loc['f096012e-2497-485d-8adb-7ec0b9352c52'].last();

You can check that it works here: http://jsfiddle.net/D4NRN/

Datageek

Use the slice() method:

my_array.slice(-1)[0]
Josh

You can also .pop off the last element. Be careful, this will change the value of the array, but that might be OK for you.

var a = [1,2,3];
a.pop(); // 3
a // [1,2]

use es6 deconstruction array with the spread operator

var last = [...yourArray].pop();

note that yourArray doesn't change.

var arr = [1, 2, 3];
arr.slice(-1).pop(); // return 3 and arr = [1, 2, 3]

This will return undefined if the array is empty and this will not change the value of the array.

amay0048
var last = array.slice(-1)[0];

I find slice at -1 useful for getting the last element (especially of an array of unknown length) and the performance is much better than calculating the length less 1.

Mozilla Docs on Slice

Performance of the various methods for selecting last array element

Underscore and Lodash have the _.last(Array) method, that returns the last element in an Array. They both work about the same

_.last([5, 4, 3, 2, 1]);
=> 1

Ramda also has a _.last function

R.last(['fi', 'fo', 'fum']); //=> 'fum'

Use JavaScript objects if this is critical to your application. You shouldn't be using raw primitives to manage critical parts of your application. As this seems to be the core of your application, you should use objects instead. I've written some code below to help get you started. The method lastLocation would return the last location.


function User(id) {
    this.id = id;

    this.locations = [];

    this.getId = function() {
        return this.id;
    };

    this.addLocation = function(latitude, longitude) {
        this.locations[this.locations.length] = new google.maps.LatLng(latitude, longitude);
    };

    this.lastLocation = function() {
        return this.locations[this.locations.length - 1];
    };

    this.removeLastLocation = function() {
        return this.locations.pop();
    };

}

function Users() {
    this.users = {};

    this.generateId = function() {
        return Math.random();
    };

    this.createUser = function() {
        var id = this.generateId();
        this.users[id] = new User(id);
        return this.users[id];
    };

    this.getUser = function(id) {
        return this.users[id];
    };

    this.removeUser = function(id) {
        var user = this.getUser(id);
        delete this.users[id];

        return user;
    };

}


var users = new Users();

var user = users.createUser();

user.addLocation(0, 0);
user.addLocation(0, 1);

You can define a getter on Array.prototype:

if (!Array.prototype.hasOwnProperty("last")) {
  Object.defineProperty(Array.prototype, "last", {
    get: function() {
      return this[this.length - 1];
    }
  });
}

console.log([9, 8, 7, 6].last); // => 6

As you can see, access doesn't look like a function call; the getter function is called internally.

In case you are using ES6 you can do:

const arr = [ 1, 2, 3 ];
[ ...arr ].pop(); // 3
arr; // [ 1, 2, 3 ] (wasn't changed)
Sreerag

This worked:

array.reverse()[0]

So, a lot of people are answering with pop(), but most of them don't seem to realize that's a destructive method.

var a = [1,2,3]
a.pop()
//3
//a is now [1,2]

So, for a really silly, nondestructive method:

var a = [1,2,3]
a[a.push(a.pop())-1]
//3

a push pop, like in the 90s :)

push appends a value to the end of an array, and returns the length of the result. so

d=[]
d.push('life') 
//=> 1
d 
//=>['life']

pop returns the value of the last item of an array, prior to it removing that value at that index. so

c = [1,2,1]
c.pop() 
//=> 1
c 
//=> [1,2]

arrays are 0 indexed, so c.length => 3, c[c.length] => undefined (because you're looking for the 4th value if you do that(this level of depth is for any hapless newbs that end up here)).

Probably not the best, or even a good method for your application, what with traffic, churn, blah. but for traversing down an array, streaming it onto another, just being silly with inefficient methods, this. Totally this.

var last = function( obj, key ) { 
    var a = obj[key];
    return a[a.length - 1];
};

last(loc, 'f096012e-2497-485d-8adb-7ec0b9352c52');
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