How to call the __invoke method of a member variable inside a class

问题

PHP 5.4.5, here. I'm trying to invoke an object which is stored as a member of some other object. Like this (very roughly)

class A {
    function __invoke () { ... }
}

class B {
    private a = new A();
 ...
    $this->a();  <-- runtime error here
}

This produces a runtime error, of course, because there's no method called a. But if I write the call like this:

($this->a)();

then I get a syntax error.

Of course, I can write

$this->a->__invoke();

but that seems intolerably ugly, and rather undermines the point of functors. I was just wondering if there is a better (or official) way.

回答1:

There's three ways:

Directly calling __invoke, which you already mentioned:

$this->a->__invoke();

By assigning to a variable:

$a = $this->a;
$a();

By using call_user_func:

call_user_func($this->a);

The last one is probably what you are looking for. It has the benefit that it works with any callable.

回答2:

I know this is a late answer, but use a combination of __call() in the parent and __invoke() in the subclass:

class A {
  function __invoke ($msg) {
    print $msg;
  }
}

class B {
    private $a;

    public function __construct() { $this->a = new A(); }

    function __call($name, $args)
    {
      if (property_exists($this, $name))
      {
        $prop = $this->$name;
        if (is_callable($prop))
        {
          return call_user_func_array($prop, $args);
        }
      }
    }
}

Then you should be able to achieve the syntactic sugar you are looking for:

$b = new B();
$b->a("Hello World\n");

回答3:

FYI in PHP 7+ parenthesis around a callback inside a object works now:

class foo {                                                                     
    public function __construct() {                                             
        $this -> bar = function() {                                             
            echo "bar!" . PHP_EOL;                                              
        };                                                                      
    }                                                                           

    public function __invoke() {                                                
        echo "invoke!" . PHP_EOL;                                               
    }                                                                           
}                                                                               

(new foo)();                                                                    

$f = new foo;                                                                   
($f -> bar)();

Result:

invoke!
bar!

来源：https://stackoverflow.com/questions/12603316/how-to-call-the-invoke-method-of-a-member-variable-inside-a-class

标签

php

function

invoke

member

functor