问题
In Go, do buffered channels have any order guarantee?
For example: you have two goroutines A & B that share a channel. A pushes data onto the channel while B reads from it. Are you guranted that B will read data In the same order that A put it into the channel?
I understand that if there are multiple producers or consumers the order may be non-deterministic, but I'm specifically asking about having just 1 producer and 1 consumer.
回答1:
You can see the idea of channel illustrated in "The Nature Of Channels In Go": it shows how the order or read/write is respected.
See also Channels:
Receivers always block until there is data to receive.
- If the channel is unbuffered, the sender blocks until the receiver has received the value.
- If the channel has a buffer, the sender blocks only until the value has been copied to the buffer; if the buffer is full, this means waiting until some receiver has retrieved a value.
Unbuffered Channels
Buffered Channel
来源：https://stackoverflow.com/questions/25795131/do-buffered-channels-maintain-order