问题
Below is my code :
ActionResult DownloadAttachment(student st)
{
var file = db.EmailAttachmentReceived.FirstOrDefault(x => x.LisaId == st.Lisaid);
byte[] fileBytes = System.IO.File.ReadAllBytes(file.Filepath);
return File(fileBytes, System.Net.Mime.MediaTypeNames.Application.Octet, file.Filename);
}
This is the script which i'm using
$(function () {
$("#DownloadAttachment").click(function () {
$.ajax({
url: '@Url.Action("DownloadAttachment", "PostDetail")',
contentType: 'application/json; charset=utf-8',
datatype: 'json',
type: "GET",
success: function () {
alert("sucess");
}
});
});
});
How to return the file for download pursing above code?
回答1:
Please, try this in ajax success
success: function () {
window.location = '@Url.Action("DownloadAttachment", "PostDetail")';
}
Updated answer:
public ActionResult DownloadAttachment(int studentId)
{
// Find user by passed id
// Student student = db.Students.FirstOrDefault(s => s.Id == studentId);
var file = db.EmailAttachmentReceived.FirstOrDefault(x => x.LisaId == studentId);
byte[] fileBytes = System.IO.File.ReadAllBytes(file.Filepath);
return File(fileBytes, System.Net.Mime.MediaTypeNames.Application.Octet, file.Filename);
}
Ajax request:
$(function () {
$("#DownloadAttachment").click(function () {
$.ajax(
{
url: '@Url.Action("DownloadAttachment", "PostDetail")',
contentType: 'application/json; charset=utf-8',
datatype: 'json',
data: {
studentId: 123
},
type: "GET",
success: function () {
window.location = '@Url.Action("DownloadAttachment", "PostDetail", new { studentId = 123 })';
}
});
});
});
回答2:
I think there is no need of Ajax call you can do simply using hyperlink as below example.
View Code
<a href="@Url.Action("DownloadAttachment", "PostDetail", new { studentId = 123 })">Download Form</a>
Controller Method
public ActionResult DownloadAttachment(int studentId)
{
// Find user by passed id
var file = db.EmailAttachmentReceived.FirstOrDefault(x => x.LisaId == studentId);
byte[] fileBytes = System.IO.File.ReadAllBytes(file.Filepath);
return File(fileBytes, System.Net.Mime.MediaTypeNames.Application.Octet, file.Filename);
}
回答3:
The following code will help you to create the pdf/excel file in server and allow to download in browser through ajax call.
Controller for creating the pdf/excel file
public async Task<JsonResult> CardStatusReportExport(ReportFilterInputModel cardStatusReportInputModel, string type, string sortOrder)
{
cardStatusReportInputModel.ReportType = Reprot_Type_Const.CardStatus;
cardStatusReportInputModel.ReportFormat = type;
var CardStatusReport = await _reportDocGeneration.DocGeneartion(cardStatusReportInputModel);
string result = Path.GetTempPath();
string fileName = "CardStatusReport" + DateTime.Now.ToString("yyyyMMddHHmmssfff");
if (type.Equals(Constants.FILE_TYPE_PDF))
{
fileName = fileName + Constants.FILE_EXTENSION_PDF;
System.IO.File.WriteAllBytes(result + fileName, CardStatusReport);
}
else
{
fileName = fileName + Constants.FILE_EXTENSION_EXCEL;
System.IO.File.WriteAllBytes(result + fileName, CardStatusReport);
}
return Json(new { fileName = fileName});
}
The following controller code will allow to download the created file from a single ajax call
[HttpGet]
public async Task<ActionResult> Download(string file)
{
var path = Path.Combine(Path.GetTempPath(),file);
var memory = new MemoryStream();
try
{
using (var stream = new FileStream(path, FileMode.Open))
{
await stream.CopyToAsync(memory);
}
}
catch (Exception e)
{
ModelState.AddModelError("FileNotFoundError", e.Message);
return Content(e.Message);
}
memory.Position = 0;
return File(memory, GetContentType(path), Path.GetFileName(path));
}
private string GetContentType(string path)
{
var types = MediaType.GetMimeTypes();
var ext = Path.GetExtension(path).ToLowerInvariant();
return types[ext];
}
Use the below ajax call for creation of pdf/excel file and download the same.
$.ajax({
method: 'POST',
data: { type: val, cardStatusReportInputModel: payload, sortOrder : sortOrder},
url: '@Url.Action("CardStatusReportExport", "Reports")'
}).done(function (data, statusText, xhdr) {
try {
if (data.fileName != "") {
window.location.href = "@Url.RouteUrl(new { Controller = "Reports", Action = "Download"})/?file=" + data.fileName;
ShowMessageAlert('@Html.Raw(Localizer["Report has been exported successfully"].Value.ToString())');
}
$("#divLoader").hide();
}
catch (e) {
$("#divLoader").hide();
}
}).fail(function (xhdr, statusText, errorText) {
alert('error');
$("#divLoader").hide();
});
回答4:
Below method would helps calling action from Ajax request from jQuery dialog window and it executes the action and can be closed dialog window as soon the action return success result
Controller
[HttpGet]
public ActionResult DownloadCampaign(string filePath, string mode)
{
string contentType = string.Empty;
var sDocument = filePath;
if (!System.IO.File.Exists(sDocument))
{
return HttpNotFound();
}
if (mode == "action")
return Json(new {fileName = filePath}, JsonRequestBehavior.AllowGet);
if (sDocument.Contains(".pdf"))
{
contentType = "application/pdf";
}
else if (sDocument.Contains(".docx"))
{
contentType = "application/docx";
}
else if (sDocument.Contains(".xls"))
{
contentType = "application/xlsx";
}
return File(sDocument, contentType, sDocument);
}
JQuery - Ajax Request
$(document)
.ready(function() {
$("#btnDownload").click(function () {
var file = $("#FilePath").val();
$.ajax({
url: '@Url.Action("DownloadCampaign", "FileList")',
data: { filePath: file, mode:'action' },
method: 'GET',
dataType: 'json',
//contentType: 'application/json; charset=utf-8',
success: function(data) {
@*window.location = '@Url.RouteUrl("DownloadCampaign", "FileList", new { filePath = data1.fileName })';*@
window.location.href = "@Url.RouteUrl(new
{ Controller = "FileList", Action = "DownloadCampaign" })/?filePath=" + data.fileName + "&mode=download";
$("#downloadFile_dialog").dialog("close");
},
error: function (req, status, errorObj) {
alert("Error");
}
});
});
});
Please reach out to me if you need more information about this.
回答5:
public FileResult DownloadGeneralDocs(string docName)
{
string fileName = docName+".pdf";
var path = _globalWebSettings.Value.DownloadGeneralDocsPath;
string filePath = "";
if (fileName!="")
{
filePath = (_env.WebRootPath + string.Format("{0}{1}",path, fileName));
}
FileInfo file1 = new FileInfo(filePath);
byte[] fileBytes = System.IO.File.ReadAllBytes(file1.FullName);
return File(fileBytes, System.Net.Mime.MediaTypeNames.Application.Octet, fileName);
}
view.cshtml:
<script>
$(document).ready(function () {
$("#docTable tbody tr td button").click(function (e) {
var docName = $(this).closest("tr").find(".document_td_data").text();
$.ajax({
url: '@Url.Action("DownloadGeneralDocs", "Documents")',
dataType: "html",
cache:false,
data: { 'docName': docName },
success: function (data) {
window.location.href = "@Url.RouteUrl(new
{ Controller = "Documents", Action = "DownloadGeneralDocs" })/?docName=" + docName ;
},
error: function (err, response) {
console.log(err, response);
alert(err, response.responseText);
}
})
});
});
来源：https://stackoverflow.com/questions/30704078/how-to-download-a-file-through-ajax-request-in-asp-net-mvc-4