问题
Possible Duplicate:
Converting 32-bit unsigned integer (big endian) to long and back
I want to translate this expression in Java
char tab[100];
tab[10] = '\xc0';
tab[48] = '\x80';
uint32_t w = 0x67452301;
uint32_t x = 0xefcdab89;
uint32_t y = 0x98badcfe;
uint32_t z = 0x10325476;
a = ((b & c) | (~b & d)) + (*(uint32_t*)(tab+0x00)) + a - 0x28955B88;
a = ((a << 0x07) | (a >> 0x19)) + b;
I'have tried this but...
char[] tab = new char[64];
tab[10] = (char) 0xc0;
tab[48] = (char) 0x80;
but the value is not the right one, is there another way to assign \0x80 in a char[] ? How can i interprete this kind of cast in java ((uint32_t)) ?
Many thanks !
回答1:
Type int is 4 bytes, i.e. 32 bits in java. So the regular 32bits int from C may be translated as regular int in java.
Unsigned int is not supported by java language, so use long that contains 8 bytes to represent unsigned 32 bit variables from C.
来源：https://stackoverflow.com/questions/11759053/using-unsigned-int-32-bit-in-java