Generate bit vector with t random ones

假装没事ソ 提交于 2019-12-06 07:18:54
std::shuffle(std::begin(v), std::end(v), g);

Doesn't make the bit position random, it just changes the positions of the existing items (which all have the zero position bit set) in the vector randomly.


If I understood your requirement correctly, What you actually should have is something like:

std::random_device rd;
std::mt19937 g(rd());
for(int i=0;i<t;i++)
     v[i] = 1 << rd(); // set a random bit position
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