How do run a Unix command at a given time interval?

问题

I want to run a Unix command (e.g. ls) at 5 minute intervals through a script.

Explanation:

I have a Unix script. In that script I have a command called "ls".

I want that "ls" command to run every 5 minutes from that script.

回答1:

Use watch. The -n flag specifies interval in seconds, so

watch -n 300 ls

回答2:

while true; do
    ls
    sleep 300
done

?

回答3:

Put your script into the Crontab via

crontab -e

More information about Cron you can find at wikipedia

回答4:

You could use crontab for example. See http://en.wikipedia.org/wiki/Cron

for example i you want to run your script every five minutes via crontab it should look something like this:

#m  h dom mon dow user command
*/5 * *   *   *   root /path/to/script

回答5:

crontab 

http://en.wikipedia.org/wiki/Cron

or

svc 

http://cr.yp.to/daemontools.html

来源：https://stackoverflow.com/questions/6758500/how-do-run-a-unix-command-at-a-given-time-interval