问题
I am using the following query in my database,
SELECT b.sales_id,b.category_id,b.sale_starts,b.sale_ends
FROM tbl_sales b WHERE b.active=1
UNION
SELECT b.sales_id,b.category_id,b.sale_starts,b.sale_ends
FROM tbl_sales b INNER JOIN tb_category c ON b.category_id=c.cat_id
WHERE c.cat_keyword LIKE 'a' ORDER BY sale_ends DESC
and getting the result as follows,
sales_id | category_id |sale_starts | sale_ends
----------|---------------------|------------|--------------
1 | 10 | 2012-03-31 | 2012-04-30
2 | 11 | 2012-03-22 | 2012-04-27
3 | 25 | 2012-03-31 | 2012-04-25
4 | 12 | 2012-04-05 | 2012-04-11
Now i need to get the result as follows, ie the row which has today's date/current date as
sale_ends must be shown in the top of the order (assuming today's date/current date is 2012-04-11
), like shown below-
sales_id | category_id |sale_starts | sale_ends
----------|---------------------|------------|--------------
4 | 12 | 2012-04-05 | 2012-04-11 (today's date)
1 | 10 | 2012-03-31 | 2012-04-30
2 | 11 | 2012-03-22 | 2012-04-27
3 | 25 | 2012-03-31 | 2012-04-25
Need help in this, thanks in advance.
回答1:
Try this ORDER BY clause with condition -
ORDER BY IF(sale_ends = DATE(NOW()), 0, 1), sale_ends DESC
回答2:
You can wrap the whole thing in another SELECT and use ORDER BY
SELECT * FROM (
SELECT b.sales_id,b.category_id,b.sale_starts,b.sale_ends
FROM tbl_sales b WHERE b.active=1
UNION
SELECT b.sales_id,b.category_id,b.sale_starts,b.sale_ends
FROM tbl_sales b INNER JOIN tb_category c ON b.category_id=c.cat_id
WHERE c.cat_keyword LIKE 'a' ORDER BY sale_ends DESC
) AS all_sales
ORDER BY (sale_ends=CURDATE()) DESC, sale_ends DESC
来源:https://stackoverflow.com/questions/10100775/mysql-query-to-show-records-with-current-date-on-top-and-others-as-per-descendin