Scrapy + Splash + ScrapyJS

问题

i am using Splash 2.0.2 + Scrapy 1.0.5 + Scrapyjs 0.1.1 and im still not able to render javascript with a click. Here is an example url https://olx.pt/anuncio/loja-nova-com-250m2-garagem-em-box-fechada-para-arrumos-IDyTzAT.html#c49d3d94cf

I am still getting the page without the phone number rendered:

class OlxSpider(scrapy.Spider):
    name = "olx"
    rotate_user_agent = True
    allowed_domains = ["olx.pt"]
    start_urls = [
        "https://olx.pt/imoveis/"
    ]

    def parse(self, response):
        script = """
        function main(splash)
            splash:go(splash.args.url)
            splash:runjs('document.getElementById("contact_methods").getElementsByTagName("span")[1].click();')
            splash:wait(0.5)
            return splash:html()
        end
        """
        for href in response.css('.link.linkWithHash.detailsLink::attr(href)'):
            url = response.urljoin(href.extract())
            yield scrapy.Request(url, callback=self.parse_house_contents, meta={
                'splash': {
                    'args': {'lua_source': script},
                    'endpoint': 'execute',
                }
            })

        for next_page in response.css('.pager .br3.brc8::attr(href)'):
            url = response.urljoin(next_page.extract())
            yield scrapy.Request(url, self.parse)

    def parse_house_contents(self, response):

        import ipdb;ipdb.set_trace()

how can i get this to work?

回答1:

You can avoid having to use Splash in the first place and make the appropriate GET request to get the phone number yourself. Working spider:

import json
import re

import scrapy   

class OlxSpider(scrapy.Spider):
    name = "olx"
    rotate_user_agent = True
    allowed_domains = ["olx.pt"]
    start_urls = [
        "https://olx.pt/imoveis/"
    ]

    def parse(self, response):
        for href in response.css('.link.linkWithHash.detailsLink::attr(href)'):
            url = response.urljoin(href.extract())
            yield scrapy.Request(url, callback=self.parse_house_contents)

        for next_page in response.css('.pager .br3.brc8::attr(href)'):
            url = response.urljoin(next_page.extract())
            yield scrapy.Request(url, self.parse)

    def parse_house_contents(self, response):
        property_id = re.search(r"ID(\w+)\.", response.url).group(1)

        phone_url = "https://olx.pt/ajax/misc/contact/phone/%s/" % property_id
        yield scrapy.Request(phone_url, callback=self.parse_phone)

    def parse_phone(self, response):
        phone_number = json.loads(response.body)["value"]
        print(phone_number)

If there are more things to extract from this "dynamic" website, see if Splash is really enough and, if not, look into browser automation and selenium.

回答2:

Add

splash:autoload("https://code.jquery.com/jquery-2.1.3.min.js")

to Lua script and it will work.

function main(splash)
    splash:go(splash.args.url)
    splash:autoload("https://code.jquery.com/jquery-2.1.3.min.js")
    splash:runjs('document.getElementById("contact_methods").getElementsByTagName("span")[1].click();')
    splash:wait(0.5)
    return splash:html()
end

.click() is JQuery function https://api.jquery.com/click/

来源：https://stackoverflow.com/questions/35780666/scrapy-splash-scrapyjs