Selecting Columns in LINQ using System.Linq.Expressions API

有些话、适合烂在心里 提交于 2019-12-06 02:04:49
 var item = Expression.Parameter(typeof(string), "x");
 var length = Expression.PropertyOrField(item, "Length");

 new string[] {"one", "two", "three"}
      .AsQueryable()
      .Select(Expression.Lambda<Func<string, int>>(length, item));

You need an IQueryable to use expressions (you can bring it back to IEnumerable with ToList or similiar). Then you generate the Lambda as an expression tree (the length example is done above). Sorry its in C#

In C# it would look like this

var myStringLengths = myStrings
                        .Select((s) => s.Length);
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