问题
I already know there are only IntStream
and LongStream
. How can I make an IntStream
from a byte array?
Currently I'm planning to do like this.
static int[] bytesToInts(final byte[] bytes) {
final int[] ints = new int[bytes.length];
for (int i = 0; i < ints.length; i++) {
ints[i] = bytes[i] & 0xFF;
}
return ints;
}
static IntStream bytesToIntStream(final byte[] bytes) {
return IntStream.of(bytesToInt(bytes));
}
Is there any easier or faster way to do this?
回答1:
A variant of Radiodef's answer:
static IntStream bytesToIntStream(byte[] bytes) {
return IntStream.range(0, bytes.length)
.map(i -> bytes[i] & 0xFF)
;
}
Easier to guarantee parallelization, too.
回答2:
You could do something like
static IntStream bytesToIntStream(byte[] bytes) {
AtomicInteger i = new AtomicInteger();
return IntStream
.generate(() -> bytes[i.getAndIncrement()] & 0xFF)
.limit(bytes.length);
}
but it's not very pretty. (It's not so bad though: usage of AtomicInteger
allows the stream to be run in parallel.)
回答3:
One line code:
import com.google.common.primitives.Bytes;
IntStream in = Bytes.asList(bytes).stream().mapToInt(i-> i & 0xFF);
来源:https://stackoverflow.com/questions/27181026/how-can-i-make-an-intstream-from-a-byte-array