Python unzipping stream of bytes?

Question

Here is the situation:

• I get gzipped xml documents from Amazon S3

  import boto
  from boto.s3.connection import S3Connection
  from boto.s3.key import Key
  conn = S3Connection('access Id', 'secret access key')
  b = conn.get_bucket('mydev.myorg')
  k = Key(b)
  k.key('documents/document.xml.gz')
  

• I read them in file as

  import gzip
  f = open('/tmp/p', 'w')
  k.get_file(f)
  f.close()
  r = gzip.open('/tmp/p', 'rb')
  file_content = r.read()
  r.close()
  

Question

How can I unzip the streams directly and read the contents?

I do not want to create temp files, they don't look good.

Answer 1

Yes, you can use the zlib module to decompress byte streams:

import zlib

def stream_gzip_decompress(stream):
    dec = zlib.decompressobj(32 + zlib.MAX_WBITS)  # offset 32 to skip the header
    for chunk in stream:
        rv = dec.decompress(chunk)
        if rv:
            yield rv

The offset of 32 signals to the zlib header that the gzip header is expected but skipped.

The S3 key object is an iterator, so you can do:

for data in stream_gzip_decompress(k):
    # do something with the decompressed data

Answer 2

I had to do the same thing and this is how I did it:

import gzip
f = StringIO.StringIO()
k.get_file(f)
f.seek(0) #This is crucial
gzf = gzip.GzipFile(fileobj=f)
file_content = gzf.read()

Answer 3

For Python3x and boto3-

So I used BytesIO to read the compressed file into a buffer object, then I used zipfile to open the decompressed stream as uncompressed data and I was able to get the datum line by line.

import io
import zipfile
import boto3
import sys

s3 = boto3.resource('s3', 'us-east-1')


def stream_zip_file():
    count = 0
    obj = s3.Object(
        bucket_name='MonkeyBusiness',
        key='/Daily/Business/Banana/{current-date}/banana.zip'
    )
    buffer = io.BytesIO(obj.get()["Body"].read())
    print (buffer)
    z = zipfile.ZipFile(buffer)
    foo2 = z.open(z.infolist()[0])
    print(sys.getsizeof(foo2))
    line_counter = 0
    for _ in foo2:
        line_counter += 1
    print (line_counter)
    z.close()


if __name__ == '__main__':
    stream_zip_file()

Answer 4

You can try PIPE and read contents without downloading file

    import subprocess
    c = subprocess.Popen(['-c','zcat -c <gzip file name>'], shell=True, stdout=subprocess.PIPE,         stderr=subprocess.PIPE)
    for row in c.stdout:
      print row

In addition "/dev/fd/" + str(c.stdout.fileno()) will provide you FIFO file name (Named pipe) which can be passed to other program.