Global exception page in Apache Tiles and Spring MVC

人走茶凉 提交于 2019-12-06 00:41:20

Assuming you have Spring's TilesViewResolver and TilesConfigurer configured, you can try the following bean definition:

<bean id="exceptionResolver" class="org.springframework.web.servlet.handler.SimpleMappingExceptionResolver">
   <property name="exceptionMappings">
      <props>
         <prop key="java.lang.Throwable">error</prop>
      </props>
   </property>
</bean>

And then simply define the logical view error:

<definition name="error" extends="common">
    <put-attribute name="body" value="/WEB-INF/jsp/error.jsp"/>
</definition>

This will forward any Throwable to the right view, where you have access to the exception itself (${exception}). This doesn't replace all standard HTTP error pages (for 404 etc.)

<tiles-definitions>
    <definition name="common" template="/WEB-INF/jsp/common.jsp">
        <put-attribute name="header" value="header"/>
        <put-attribute name="footer" value="/WEB-INF/jsp/footer.jsp"/>
    </definition>
   <definition name="common11" template="/WEB-INF/jsp/common11.jsp">//common11 is same page as common.jsp
        <put-attribute name="header" value=""/>
        <put-attribute name="footer" value=""/>
    </definition>
   ...
   <definition name="main" extends="common">
       <put-attribute name="body" value="/WEB-INF/jsp/main.jsp"/>
       <put-attribute name="header" value=""/>
        <put-attribute name="footer" value=""/>
   </definition>
</tiles-definitions>

If you are using struts 2.0 then in struts.xml, You can use as following, Or if you are using jsp servlet then you can use following in web.xml

<global-results>
<result name="error">/WEB-INF/jsp/common.jsp</result>
</global-results>
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