Determine whether a file is a junction (in Windows) or not?

问题

I've been searching around trying to find a way to determine if a file is a junction or not, and have not found any satisfactory answers.

First thing I tried was:

Files.isSymbolicLink(aPath)

It detects only symbolic links not the files referred to as junctions in Windows.

Also tried the solution proposed here (using JNA library): Stackoverflow question (3249117) , but it never returned true on any of the files I know to be junctions.

The only way I've found to determine which files are junctions is the following command run in windows command prompt:

DIR /S /A:L

On my computer it returns 66 folders, wheras Files.isSymbolicLink(aPath) returned only 2. So I suppose I could find a way to utilize this, but I don't think it would be very effiecient when traversing a filetree.

Is there any way to do this using the standard java library, or alternativly JNA?

回答1:

If you can write native code in JNA, you can directly call the Win32 API GetFileAttributes() function and check for the FILE_ATTRIBUTE_REPARSE_POINT flag (junctions are implemented as reparse points).

Update: To differentiate between different types of reparse points, you have to retreive the ReparseTag of the actual reparse point. For a junction point, it will be set to IO_REPARSE_TAG_MOUNT_POINT (0xA0000003).

There are two ways to retreive the ReparseTag:

Use DeviceIoControl() with the FSCTL_GET_REPARSE_POINT control code to obtain an REPARSE_DATA_BUFFER struct, which as a ReparseTag field. You can see an example of an IsDirectoryJunction() implementation using this technique in the following article:

NTFS Hard Links, Directory Junctions, and Windows Shortcuts
Use FindFirstFile() to obtain a WIN32_FIND_DATA struct. If the path has the FILE_ATTRIBUTE_REPARSE_POINT attribute, the dwReserved0 field will contain the ReparseTag.

回答2:

There can be a way to do it without JNA, if you have the right java, such as Oracle jdk 8. It's dodgy, it can cease to work, but....

You can get BasicFileAttributes interface related to the link:

BasicFileAttributes attr = Files.readAttributes(path, BasicFileAttributes.class, LinkOption.NOFOLLOW_LINKS);

It can happen that this interface implementation is a class sun.nio.fs.WindowsFileAttributes. And this class has a method isReparsePoint, which returns true for both junction points and symbolic links. So you can try to use reflection and call the method:

    boolean isReparsePoint = false;
    if (DosFileAttributes.class.isInstance(attr))
        try {
            Method m = attr.getClass().getDeclaredMethod("isReparsePoint");
            m.setAccessible(true);
            isReparsePoint = (boolean) m.invoke(attr);
        } catch (Exception e) {
            // just gave it a try
        }

Now you only can discover whether it really is symbolic link: Files.isSymbolicLink(path)

If its not, but it is reparse point, then that's junction.

回答3:

With J2SE 1.7 use Java NIO

/**
* returns true if the Path is a Windows Junction
*/
private static boolean isJunction(Path p) {
    boolean isJunction = false;
    try {
        isJunction = (p.compareTo(p.toRealPath()) != 0);
    } catch (IOException e) {
        e.printStackTrace(); // TODO: handleMeProperly
    }
    return isJunction;
}

回答4:

While on Windows a junction's attributes have isSymbolicLink() == false, they have isOther() == true. So you could do something like:

boolean isWindows = System.getProperty("os.name").toLowerCase().contains("windows")
BasicFileAttributes attrs = Files.readAttributes(aPath, BasicFileAttributes.class);
boolean isJunction = isWindows && attrs.isDirectory() && attrs.isOther();

来源：https://stackoverflow.com/questions/13733275/determine-whether-a-file-is-a-junction-in-windows-or-not

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java

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