Sequelize - Join with multiple column

Question

I like to convert the following query into sequelize code

select * from table_a 
inner join table_b 
on table_a.column_1 = table_b.column_1
and table_a.column_2 = table_b.column_2

I have tried many approaches and followed many provided solution but I am unable to achieve the desired query from sequelize code.

The max I achieve is following :

select * from table_a 
inner join table_b 
on table_a.column_1 = table_b.column_1

I want the second condition also.

and table_a.column_2 = table_b.column_2

any proper way to achieve it?

Answer 1

You need to define your own on clause of the JOIN statement

ModelA.findAll({
    include: [
        {
            model: ModelB,
            on: {
                col1: sequelize.where(sequelize.col("ModelA.col1"), "=", sequelize.col("ModelB.col1")),
                col2: sequelize.where(sequelize.col("ModelA.col2"), "=", sequelize.col("ModelB.col2"))
            },
            attributes: [] // empty array means that no column from ModelB will be returned
        }
    ]
}).then((modelAInstances) => {
    // result...
});