Java generics - why is “extends T” allowed but not “implements T”?

问题

I wonder if there is a special reason in Java for using always \"extends\" rather than \"implements\" for defining bounds of typeparameters.

Example:

public interface C {}
public class A<B implements C>{} 

is prohibited but

public class A<B extends C>{} 

is correct. What is the reason for that?

回答1:

There is no semantic difference in the generic constraint language between whether a class 'implements' or 'extends'. The constraint possibilities are 'extends' and 'super' - that is, is this class to operate with assignable to that other one (extends), or is this class assignable from that one (super).

回答2:

The answer is in here :

To declare a bounded type parameter, list the type parameter's name, followed by the extends keyword, followed by its upper bound […]. Note that, in this context, extends is used in a general sense to mean either extends (as in classes) or implements (as in interfaces).

So there you have it, it's a bit confusing, and Oracle knows it.

回答3:

Probably because for both sides (B and C) only the type is relevant, not the implementation. In your example

public class A<B extends C>{}

B can be an interface as well. "extends" is used to define sub-interfaces as well as sub-classes.

interface IntfSub extends IntfSuper {}
class ClzSub extends ClzSuper {}

I usually think of 'Sub extends Super' as 'Sub is like Super, but with additional capabilities', and 'Clz implements Intf' as 'Clz is a realization of Intf'. In your example, this would match: B is like C, but with additional capabilities. The capabilities are relevant here, not the realization.

回答4:

It may be that the base type is a generic parameter, so the actual type may be an interface of a class. Consider:

class MyGen<T, U extends T> {

Also from client code perspective interfaces are almost indistinguishable from classes, whereas for subtype it is important.

回答5:

Here is a more involved example of where extends is allowed and possibly what you want:

public class A<T1 extends Comparable<T1>>

回答6:

It's sort of arbitrary which of the terms to use. It could have been either way. Perhaps the language designers thought of "extends" as the most fundamental term, and "implements" as the special case for interfaces.

But I think implements would make slightly more sense. I think that communicates more that the parameter types don't have to be in an inheritance relationship, they can be in any kind of subtype relationship.

The Java Glossary expresses a similar view.

回答7:

We are used to

class ClassTypeA implements InterfaceTypeA {}
class ClassTypeB extends ClassTypeA {}

and any slight deviation from these rules greatly confuses us.

The syntax of a type bound is defined as

TypeBound:
    extends TypeVariable 
    extends ClassOrInterfaceType {AdditionalBound}

^{(JLS 12 > 4.4. Type Variables > TypeBound)}

If we were to change it, we would surely add the implements case

TypeBound:
    extends TypeVariable 
    extends ClassType {AdditionalBound}
    implements InterfaceType {AdditionalBound}

and end up with two identically processed clauses

ClassOrInterfaceType:
    ClassType 
    InterfaceType

^{(JLS 12 > 4.3. Reference Types and Values > ClassOrInterfaceType)}

except we would also need to take care of implements, which would complicate things further.

I believe it's the main reason why extends ClassOrInterfaceType is used instead of extends ClassType and implements InterfaceType - to keep things simple within the complicated concept. The problem is we don't have the right word to cover both extends and implements and we definitely don't want to introduce one.

<T is ClassTypeA>
<T is InterfaceTypeA>

Although extends brings some mess when it goes along with an interface, it's a broader term and it can be used to describe both cases. Try to tune your mind to the concept of extending a type (not extending a class, not implementing an interface). You restrict a type parameter by another type and it doesn't matter what that type actually is. It only matters that it's its upper bound and it's its supertype.

来源：https://stackoverflow.com/questions/976441/java-generics-why-is-extends-t-allowed-but-not-implements-t