问题

How can I display this:

Decimal(\'40800000000.00000000000000\') as \'4.08E+10\'?

I\'ve tried this:

>>> \'%E\' % Decimal(\'40800000000.00000000000000\')
\'4.080000E+10\'

But it has those extra 0\'s.

回答1:

from decimal import Decimal

'%.2E' % Decimal('40800000000.00000000000000')

# returns '4.08E+10'

In your '40800000000.00000000000000' there are many more significant zeros that have the same meaning as any other digit. That's why you have to tell explicitly where you want to stop.

If you want to remove all trailing zeros automatically, you can try:

def format_e(n):
    a = '%E' % n
    return a.split('E')[0].rstrip('0').rstrip('.') + 'E' + a.split('E')[1]

format_e(Decimal('40800000000.00000000000000'))
# '4.08E+10'

format_e(Decimal('40000000000.00000000000000'))
# '4E+10'

format_e(Decimal('40812300000.00000000000000'))
# '4.08123E+10'

回答2:

Here's an example using the format() function:

>>> "{:.2E}".format(Decimal('40800000000.00000000000000'))
'4.08E+10'

official documentation
original format() proposal

回答3:

Given your number

x = Decimal('40800000000.00000000000000')

Starting from Python 3,

'{:.2e}'.format(x)

is the recommended way to do it.

e means you want scientific notation, and .2 means you want 2 digits after the dot. So you will get x.xxE±n

回答4:

No one mentioned the short form of the .format method:

Needs at least Python 3.6

f"{Decimal('40800000000.00000000000000'):.2E}"

(I believe it's the same as Cees Timmerman, just a bit shorter)

回答5:

See tables from Python string formatting to select the proper format layout. In your case it's %.2E.

回答6:

My decimals are too big for %E so I had to improvize:

def format_decimal(x, prec=2):
    tup = x.as_tuple()
    digits = list(tup.digits[:prec + 1])
    sign = '-' if tup.sign else ''
    dec = ''.join(str(i) for i in digits[1:])
    exp = x.adjusted()
    return '{sign}{int}.{dec}e{exp}'.format(sign=sign, int=digits[0], dec=dec, exp=exp)

Here's an example usage:

>>> n = decimal.Decimal(4.3) ** 12314
>>> print format_decimal(n)
3.39e7800
>>> print '%e' % n
inf

回答7:

This worked best for me:

import decimal
'%.2E' % decimal.Decimal('40800000000.00000000000000')
# 4.08E+10

回答8:

To convert a Decimal to scientific notation without needing to specify the precision in the format string, and without including trailing zeros, I'm currently using

def sci_str(dec):
    return ('{:.' + str(len(dec.normalize().as_tuple().digits) - 1) + 'E}').format(dec)

print( sci_str( Decimal('123.456000') ) )    # 1.23456E+2

To keep any trailing zeros, just remove the normalize().

回答9:

I prefer Python 3.x way.

cal = 123.4567
print(f"result {cal:.4E}")

4 indicates how many digits are shown shown in the floating part.

cal = 123.4567
totalDigitInFloatingPArt = 4
print(f"result {cal:.{totalDigitInFloatingPArt}E} ")

回答10:

This is a consolidated list of the "Simple" Answers & Comments.

PYTHON 3

from decimal import Decimal

x = '40800000000.00000000000000'
# Converted to Float
x = Decimal(x)

# ===================================== # `Dot Format`
print("{0:.2E}".format(x))
# ===================================== # `%` Format
print("%.2E" % x)
# ===================================== # `f` Format
print(f"{x:.2E}")
# =====================================
# ALL Return: 4.08E+10
print((f"{x:.2E}") == ("%.2E" % x) == ("{0:.2E}".format(x)))
# True
print(type(f"{x:.2E}") == type("%.2E" % x) == type("{0:.2E}".format(x)))
# True
# =====================================

OR Without `IMPORT`'s

# NO IMPORT NEEDED FOR BASIC FLOATS
y = '40800000000.00000000000000'
y = float(y)

# ===================================== # `Dot Format`
print("{0:.2E}".format(y))
# ===================================== # `%` Format
print("%.2E" % y)
# ===================================== # `f` Format
print(f"{y:.2E}")
# =====================================
# ALL Return: 4.08E+10
print((f"{y:.2E}") == ("%.2E" % y) == ("{0:.2E}".format(y)))
# True
print(type(f"{y:.2E}") == type("%.2E" % y) == type("{0:.2E}".format(y)))
# True
# =====================================

Comparing

# =====================================
x
# Decimal('40800000000.00000000000000')
y
# 40800000000.0

type(x)
# <class 'decimal.Decimal'>
type(y)
# <class 'float'>

x == y
# True
type(x) == type(y)
# False

x
# Decimal('40800000000.00000000000000')
y
# 40800000000.0

So for Python 3, you can switch between any of the three for now.

My Fav:

print("{0:.2E}".format(y))

回答11:

def formatE_decimal(x, prec=2):
    """ Examples:
    >>> formatE_decimal('0.1613965',10)
    '1.6139650000E-01'
    >>> formatE_decimal('0.1613965',5)
    '1.61397E-01'
    >>> formatE_decimal('0.9995',2)
    '1.00E+00'
    """
    xx=decimal.Decimal(x) if type(x)==type("") else x 
    tup = xx.as_tuple()
    xx=xx.quantize( decimal.Decimal("1E{0}".format(len(tup[1])+tup[2]-prec-1)), decimal.ROUND_HALF_UP )
    tup = xx.as_tuple()
    exp = xx.adjusted()
    sign = '-' if tup.sign else ''
    dec = ''.join(str(i) for i in tup[1][1:prec+1])   
    if prec>0:
        return '{sign}{int}.{dec}E{exp:+03d}'.format(sign=sign, int=tup[1][0], dec=dec, exp=exp)
    elif prec==0:
        return '{sign}{int}E{exp:+03d}'.format(sign=sign, int=tup[1][0], exp=exp)
    else:
        return None

来源：https://stackoverflow.com/questions/6913532/display-a-decimal-in-scientific-notation

标签

python

string-formatting

Display a decimal in scientific notation

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