Remove accents from a dataframe column in R

孤街浪徒 提交于 2019-12-05 03:47:22

Ok the way to solve the problem :

Encoding(base$terme[2])
[1] "UTF-8"
iconv(base$terme[2],from="UTF-8",to="ASCII//TRANSLIT")
[1] "Millesime"

Thanks to @nicola

It might be easier to use the package. This way, you don't need to check the encoding beforehand. Furthermore is consistent across operating systems and inconv is not.

library(stringi)

base <- data.table(terme = c("Millésime", 
                             "boulangère", 
                             "üéâäàåçêëèïîì"))

base[, terme := stri_trans_general(str = terme, 
                                   id = "Latin-ASCII")]

> base
           terme
1:     Millesime
2:    boulangere
3: ueaaaaceeeiii

You can apply this function

    rm_accent <- function(str,pattern="all") {
   if(!is.character(str))
    str <- as.character(str)

  pattern <- unique(pattern)

  if(any(pattern=="Ç"))
    pattern[pattern=="Ç"] <- "ç"

  symbols <- c(
    acute = "áéíóúÁÉÍÓÚýÝ",
    grave = "àèìòùÀÈÌÒÙ",
    circunflex = "âêîôûÂÊÎÔÛ",
    tilde = "ãõÃÕñÑ",
    umlaut = "äëïöüÄËÏÖÜÿ",
    cedil = "çÇ"
  )

  nudeSymbols <- c(
    acute = "aeiouAEIOUyY",
    grave = "aeiouAEIOU",
    circunflex = "aeiouAEIOU",
    tilde = "aoAOnN",
    umlaut = "aeiouAEIOUy",
    cedil = "cC"
  )

  accentTypes <- c("´","`","^","~","¨","ç")

  if(any(c("all","al","a","todos","t","to","tod","todo")%in%pattern)) # opcao retirar todos
    return(chartr(paste(symbols, collapse=""), paste(nudeSymbols, collapse=""), str))

  for(i in which(accentTypes%in%pattern))
    str <- chartr(symbols[i],nudeSymbols[i], str) 

  return(str)
}
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