Access nested children in xml file parsed with ElementTree

我怕爱的太早我们不能终老 提交于 2019-12-05 00:11:32
Keerthana Prabhakaran

Yo have to iter() over your root.

that is root.iter() would do the trick!

import xml.etree.ElementTree as ET
import urllib2
tree =ET.parse(urllib2.urlopen('http://ratings.food.gov.uk/OpenDataFiles/FHRS408en-GB.xml'))
root = tree.getroot()
for child in root.iter():
   print child.tag, child.attrib

Output:

FHRSEstablishment {}
Header {}
ExtractDate {}
ItemCount {}
ReturnCode {}
EstablishmentCollection {}
EstablishmentDetail {}
FHRSID {}
LocalAuthorityBusinessID {}
...
  • To get all tags inside EstablishmentDetail you need to find that tag and then loop through its children!

That is, for example.

for child in root.find('.//EstablishmentDetail'):
    print child.tag, child.attrib

Output:

FHRSID {}
LocalAuthorityBusinessID {}
BusinessName {}
BusinessType {}
BusinessTypeID {}
RatingValue {}
RatingKey {}
RatingDate {}
LocalAuthorityCode {}
LocalAuthorityName {}
LocalAuthorityWebSite {}
LocalAuthorityEmailAddress {}
Scores {}
SchemeType {}
NewRatingPending {}
Geocode {}
  • To get the score for Hygiene as you've mentioned in comment,

What you have done is, it will get the first Scores tag and that will have Hygiene, ConfidenceInManagement, Structural tags as child when you call for each in root.find('.//Scores'):rating=child.get('Hygiene'). That is, obviously all three child will not have the element!

You need to first - find all Scores tag. - find Hygiene in every tags found!

for each in root.findall('.//Scores'):
    rating = each.find('.//Hygiene')
    print '' if rating is None else rating.text

Output:

5
5
5
0
5

Hope it could be useful:

import xml.etree.ElementTree as etree
with open('filename.xml') as tmpfile:
    doc = etree.iterparse(tmpfile, events=("start", "end"))
    doc = iter(doc)
    event, root = doc.next()
    num = 0
    for event, elem in doc:
        print event, elem
易学教程内所有资源均来自网络或用户发布的内容,如有违反法律规定的内容欢迎反馈
该文章没有解决你所遇到的问题?点击提问,说说你的问题,让更多的人一起探讨吧!