Bash list files with range

Question

My script has to list all files between a given range of date within a file name (ex: 20130133.212001.log). The start date and end date will be given by user. I now have start_year, end_year, start_month, end_month....so on till end_second. My plan was to use ls syntax:

ls *{start_year..end_year}{start_month..end_month}{.....}.log

But the problem is if month or date has 01 bash is taking it as 1. Indeed my bash version is older than 4. I can't considering updating the bash version. Any other method that I use to list files in such range.

[EDIT]

$> cat tmp.sh
#! /bin/bash

start_year=2013
end_year=2013
start_month=01
end_month=01
start_date=01
end_date=12

start_month=$(printf %02d $start_month)
end_month=$(printf %02d $end_month)

start_date=$(printf %02d $start_date)
end_date=$(printf %02d $end_date)
ls {$start_year..$end_year}{$start_month..$end_month}{$start_date..$end_date}.log
$> 

but output is:

$>./tmp.sh
ls: {2013..2013}{01..01}{01..12}.log: No such file or directory

while the current dir contains:

$> ls
20130101.log  20130103.log  20130105.log  20130107.log  20130109.log  20130111.log  20130201.log  abcd.log
20130102.log  20130104.log  20130106.log  20130108.log  20130110.log  20130112.log  2013.log      tmp.sh
$> 

Answer 1

How about like this:

start=$start_year$(printf %02d $start_month)
end=$end_year$(printf %02d $end_month)
ls *.log | sed -ne "/$start/,/$end/p"

Answer 2

You can utilize printf facility in that case.

Consider this script:

for i in {1..2}; do for j in {01..12}; do printf "%02d%02d\n" $i $j; done; done

**UPDATE: For using variable:

start=1
end=2
for ((i=start; i<=end; i++)); do
   for ((j=1; j<=12; j++)); do printf "%02d%02d\n" $i $j; done
done

0101
0102
0103
0104
0105
0106
0107
0108
0109
0110
0111
0112
0201
0202
0203
0204
0205
0206
0207
0208
0209
0210
0211
0212