Hibernate Enumeration Mapping

做~自己de王妃 提交于 2019-12-04 20:45:53
mtpettyp

Look at GenericEnumUserType described at hibernate.org (Under "Flexible solution")

If you're using Hibernate 4 you'll have to use a modified version as discussed here

Since you're locked into a varchar for column type, I think you're looking at a custom UserType. Such as: http://docs.jboss.org/hibernate/orm/4.0/manual/en-US/html/types.html#types-custom-ut

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