Getting only required objects from a list using Java 8 Streams

问题

Consider a Parent class with the attributes attrib1, attrib2 and List<Child> child with its corresponding getters and setters.

The Child is another class with five attributes attrib1-attrib5 with its corresponding getters and setters.

Now I created a List<Parent> parent. Then I want to filter out a List<Parent> with following condition:- Child.Attrib1 > 10;

So I created the following query by Java 8 streams.

parent.stream().filter(e -> e.getChild().stream().anyMatch(c -> c.getAttrib1() > 10));

But the problem is I will get all the child in each Parent object. Here I want to get only those child object in List<Child> that obeys the given condition.

How should I remove all the child objects in List that doesn't obeys the condition and get the new List.

回答1:

What you need is a Stream<Child> if you want to receive all children. The following expression might do the trick:

parents.stream().flatMap(e -> e.getChildren().stream()).filter(c -> c.getAttrib1() > 10)

This should return all children of all parents in the list where the get attribute value is greater than 10.

If you want to update the parents list by removing all child elements that fail a condition, you can do the following:

parents.forEach(p -> p.getChildren().removeIf(c -> c.getAttrib1() > 10));

This doesn't create a new list. Instead it updates the parents list itself.

回答2:

As I can understand you should add additional filter for child lists:

 parent.stream().filter(e -> e.getChild().stream().anyMatch(c -> c.getAttrib1() > 10)).forEach(e -> e.setChild(e.getChild().stream().filter(c -> c.getAttrib1 > 10).collect(toList())))

If you have not setChild:

You can remove items from lists
Create completly new parent objects

To remove you can use iterator:

parent.stream().filter(e -> e.getChild().stream().anyMatch(c -> c.getAttrib1 > 10))
   .forEach(e -> {
      for(Iterator<Child> it = e.getChild().iterator(); it.hasNext();){
          Child cur = it.next();
          if(cur.getAttrib1() <= 10) it.remove();
    }
})

回答3:

I know the question is almost 2 years old, but hopefully this answer can help someone.

There's a library called com.coopstools.cachemonads. It extends the java stream (and Optional) classes to allow caching of entities for later use.

The solution can be found with:

List<Parent> goodParents = CacheStream.of(parents)
            .cache()
            .map(Parent::getChildren)
            .flatMap(Collection::stream)
            .map(Child::getAttrib1)
            .filter(att -> att > 10)
            .load()
            .distinct()
            .collect(Collectors.toList());

where, parents is an array or stream.

For clarity, the cache method is what stores the parents; and the load method is what pulls the parents back out. And If a parent does not have children, a filter will be needed after the first map to remove the null lists.

This library can be used in any situation where operations need to be performed on children, including map/sort/filter/etc, but where an older entity is still needed.

The code can be found at https://github.com/coopstools/cachemonads (where I've included your example in the readme), or can be downloaded from maven:

<dependency>
    <groupId>com.coopstools</groupId>
    <artifactId>cachemonads</artifactId>
    <version>0.2.0</version>
</dependency>

(or, gradle, com.coopstools:cachemonads:0.2.0)

来源：https://stackoverflow.com/questions/32132387/getting-only-required-objects-from-a-list-using-java-8-streams

标签

java

arraylist

java-8

java-stream