Convert a bigint to a string in Go

问题

How do one convert a big int to a string (or integer) in Golang?

bigint := big.NewInt(123) //This is what I have
bigstr = "123" //This is what I want

回答1:

Just use the String method : http://golang.org/pkg/math/big/#Int.String

bigint := big.NewInt(123)
bigstr := bigint.String()

回答2:

I used the following:

bigint := big.NewInt(1231231231231)
bigstr := fmt.Sprint(bigint)

回答3:

You asked how to convert a bigInt to string or to int, the accepted answer explains only how to convert to string.

So you have your bigint := big.NewInt(123)

---

You can convert your bigInt to integer in two possible ways:

• using .Int64(). With yourInt := bigint.Int64()
• using .Uint64(). With yourUint := bigint.Uint64()

The reason for two methods is that uint holds 2 time bigger numbers, and sometimes you know that the answer is positive. Beware that if the number is bigger than the maximum possible for int64/uint64:

If x cannot be represented in an int64, the result is undefined.

---

And for completeness, to convert to string, just use .String() bigstr := bigint.String()

来源：https://stackoverflow.com/questions/11810948/convert-a-bigint-to-a-string-in-go