Mongodb $in against a field of objects of array instead of objects of array

问题

arr=[{field1:<value1>,field2:<value2}.....]

I want to use the $in operator against the field1 of arr. I know I could create a dummy array and push the field1 values in the dummy array. But is there a way to use the $in operator against a particular field of an array?

The arr array is no way related to the collection.

I want to query all the documents on a particular field whose value is in the field1 of arr - field1 should be in the right hand side of operator $in

Example:

arr=[{name:'foo',location:'NY'},{name:'bar',location:'LA'},{name:'foobar',location:'NZ'}]

db.collection.find({fieldx:<Here I want some method to obtain all documents whose fieldx values are in the location field of arr>})

The output should contain documents whose fieldx values are present in the location field of arr.

The ouput of the query should be

[{... 
    fieldx:'NY',
...
},
{...
    fieldx:'LA',
...
},
{...
    fieldx:'NZ',
...
}]

fieldx is the field in the collection I am querying on. It is not a field of the array I'm providing(arr). I want to match this to a field(location) of array - arr I'm providing the query.

回答1:

You need to extract the "location" fields from your input array and feed them to $in:

var locs = arr.map(function(x) { return x.location } );
db.collection.find({ "fieldx": { "$in": locs } })

---

For reference here I'm going to re-write your question for you:

I have a collection that contains documents like this:

{ "fieldx": "NY" }
{ "fieldx": "LA" }
{ "fieldx": "SF" }

What I have is an input array that is defined like this:

var arr = [
    { "name": "foo", "location": "NY"},
    { "name": "bar", "location": "LA"},
    { "name": "foobar", "location": "NZ"}
];

Now I want to write a query to find all the documents that match the "location" field in the array I have for input.

How do I do I do that?

I have tried:

db.collection.find({ "fieldx": { "$in": arr } })

But that does not match.

回答2:

Extending Neil Lunn's answers, you can use map function within query also.

var arr = [
    { "name": "foo", "location": "NY"},
    { "name": "bar", "location": "LA"},
    { "name": "foobar", "location": "NZ"}
];

db.collection.find({ "fieldx": { "$in": arr.map(function(x) { return x.location } ) } })

If you using ES6 syntax then

db.collection.find({ "fieldx": { "$in": arr.map(x => x.location ) } })

回答3:

You need to use dot notation to select fields in the array:

db.coll.find({"arr.field1" : { $in : [ 'value1', 'value11' ]}});

This query will return all documents where array arr contains at least one subdocument that has a field field1 with values value1 or value11.

Edit

Regarding your edit, you can't use $in operator that way.

From the documentation:

The $in operator selects the documents where the value of a field equals any value in the specified array.

If you send an array of objects in the $in query it will match document where specified field contains that object:

db.coll.find({ a: { $in : [ { b : 1, c: 1}, { b : 2, c: 2}  ]}});

Will find this documents:

{ 
    _id : ...
    a: { b : 1, c: 1} 
}
{ 
    _id : ...
    a: { b : 2, c: 2} 
}

To get what you really want, easiest way to query is to extract the values from your array of objects and do a query with the created array of values.

来源：https://stackoverflow.com/questions/24503323/mongodb-in-against-a-field-of-objects-of-array-instead-of-objects-of-array