PHP date format, remove time and more [duplicate]

问题

This question already has answers here:

Closed 7 years ago.

Possible Duplicate:
Convert one date format into another in PHP

Starting from:

$date = '2012-09-09 03:09:00'

I would like to do two things.

1. Remove the time from the string, so it will become "2012-09-09".
2. Calculate how many years, days, and hours have passed since this date using the server current date/time/timezone.

Could anyone help me figure this out?

回答1:

Use DateTime:

$date = '2012-09-09 03:09:00';

$createDate = new DateTime($date);

$strip = $createDate->format('Y-m-d');
var_dump($strip); // string(10) "2012-09-09"

$now = new DateTime();
$difference = $now->diff($createDate, true);
var_dump($difference);

/* object(DateInterval)#3 (8) {
  ["y"]=>
  int(0)
  ["m"]=>
  int(0)
  ["d"]=>
  int(7)
  ["h"]=>
  int(13)
  ["i"]=>
  int(4)
  ["s"]=>
  int(38)
  ["invert"]=>
  int(0)
  ["days"]=>
  int(7)
} */

回答2:

$date = '2012-09-09 03:09:00';
$dt = new DateTime($date);

echo $dt->format('Y-m-d');

$interval = $dt->diff(new DateTime());

You can use the interval as it suits you. See http://php.net/manual/en/class.dateinterval.php

来源：https://stackoverflow.com/questions/12447110/php-date-format-remove-time-and-more