问题
I had the code:
std::string st = "SomeText";
...
std::cout << st;
and that worked fine. But now my team wants to move to wstring
.
So I tried:
std::wstring st = "SomeText";
...
std::cout << st;
but this gave me a compilation error:
Error 1 error C2664: 'std::basic_string<_Elem,_Traits,_Ax>::basic_string(const std::basic_string<_Elem,_Traits,_Ax> &)' : cannot convert parameter 1 from 'const char [8]' to 'const std::basic_string<_Elem,_Traits,_Ax> &' D:...\TestModule1.cpp 28 1 TestModule1
After searching the web I read that I should define it as:
std::wstring st = L"SomeText"; // Notice the "L"
...
std::cout << st;
this compiled but prints "0000000000012342"
instead of "SomeText"
.
What am I doing wrong ?
回答1:
To display a wstring you also need a wide version of cout - wcout.
std::wstring st = L"SomeText";
...
std::wcout << st;
回答2:
Use std::wcout
instead of std::cout
.
回答3:
This answer apply to "C++/CLI" tag, and related Windows C++ console.
If you got multi-bytes characters in std::wstring, two more things need to be done to make it work:
- Include headers
#include <io.h>
#include <fcntl.h>
- Set stdout mode
_setmode(_fileno(stdout), _O_U16TEXT)
Result:
回答4:
try to use use std::wcout<<st
it will fix your problem.
std::wstring st = "SomeText";
...
std::wcout << st;
来源:https://stackoverflow.com/questions/8788057/how-to-initialize-and-print-a-stdwstring