问题

I have a date in XMLGregorianCalendar format like "2013-05-16T09:54:13" which i have to convert to timestamp "MM/DD/YYYY hh:mm:ss AM" for inserting into oracle database table using java.

how can i do this in Java?

回答1:

You can do this to return a Date:

calendar.toGregorianCalendar().getTime()

I found that code from this tutorial. From there, you can use a SimpleDateFormat to turn it into a string in the format you want.

But, if you're using JDBC to save the date in the database, you probably can pass in the Date directly with this method:

preparedStatement.setDate(colNum, myDate);

回答2:

Here is more clear answer:

Get instance of Date from XMLGregorianCalendar instance:

Date date = xmlCalendar.toGregorianCalendar().getTime();

I found that code from Convert XMLGregorianCalendar to Date in Java

Format that Date instance with format "MM/dd/yyyy hh:mm:ss a", you will get MM/DD/YYYY hh:mm:ss AM format

DateFormat  formatter = new SimpleDateFormat("MM/dd/yyyy hh:mm:ss a");
String formattedDate  = formatter.format(date)

From Convert Date to String in Java

For inserting database you would do what Daniel suggested

回答3:

If you want to insert your date on a database I would first do what Daniel suggested:

XMLGregorianCalendar xgc=<assume this is initialized>;
Date timestamp=xgc.toGregorianCalendar().getTime();

and later insert it through a PreparedStatement as Timestamp in milliseconds (Epoch time). That way you won't loose precision.

preparedStatement.setTimestamp(colNum,new Timestamp(timestamp.getTime()));

回答4:

tl;dr

myPreparedStatement.setObject( 
    … , 
    myXGC.toGregorianCalendar()
         .toZonedDateTime()
) ;

java.time

The modern approach uses the java.time classes that supplanted the troublesome old classes Date, Calendar, and GregorianCalendar.

Convert from the legacy classes to java.time.

GregorianCalendar gc = myXGC.toGregorianCalendar() ;
ZonedDateTime zdt = gc.toZonedDateTime();

Pass date-time values to your database as date-time objects rather than as strings.

If your JDBC driver complies with JDBC 4.2 and later, you can deal directly with java.time types.

myPreparedStatement.setObject( … , zdt ) ;

If your driver is not yet compliant, convert briefly to a java.sql type.

myPreparedStatement.setTimestamp( … , java.sql.Timestamp.from ( zdt.toInstant() ) ) ;

回答5:

Use the DateFormat class in Java. This should be helpful: http://docs.oracle.com/javase/6/docs/api/java/text/DateFormat.html

回答6:

You can convert XMLGregorianCalendar to java.util.Date Object by using these two lines of code :-

Date date = xmlDate.toGregorianCalendar().getTime();
System.out.println("java.util.date :- " + date);

To convert to java.slq.Date Object use this code :-

long time = xmlDate.toGregorianCalendar().getTime().getTime();
java.sql.Date sqlDate = new java.sql.Date(time);

You can see complete example here

回答7:

Please use the function below - just pass the XMLGregorianCalendar instance and date format you want (format example: "DD MMMM yyyy" -> 01 January 2017)

public String parseDate(String format,XMLGregorianCalendar XMLdate){
    Date date = XMLdate.toGregorianCalendar().getTime();
    DateFormat  formatter = new SimpleDateFormat(format);
    String formattedDate  = formatter.format(date);
    return formattedDate;
}

回答8:

This returns java.util.Date:

java.util.Date tempDate = issueDate.toGregorianCalendar().getTime();

来源：https://stackoverflow.com/questions/16706431/convert-xmlgregoriancalendar-to-date-i-e-mm-dd-yyyy-hhmmss-am

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java

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oracle11g

convert XMLGregorianCalendar to date i.e “MM/DD/YYYY hh:mm:ss AM”

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