Converting a str to a &[u8]

问题

This seems trivial, but I cannot find a way to do it.

For example,

fn f(s: &[u8]) {}

pub fn main() {
    let x = "a";
    f(x)
}

Fails to compile with:

error: mismatched types:
 expected `&[u8]`,
    found `&str`
(expected slice,
    found str) [E0308]

documentation, however, states that:

The actual representation of strs have direct mappings to slices: &str is the same as &[u8].

回答1:

You can use the as_bytes method:

fn f(s: &[u8]) {}

pub fn main() {
    let x = "a";
    f(x.as_bytes())
}

or, in your specific example, you could use a byte literal:

let x = b"a";
f(x)

来源：https://stackoverflow.com/questions/31289588/converting-a-str-to-a-u8