Postgres SELECT* FROM table WHERE column-varchar==“string-example”?

Question

I have the following table:

CREATE TABLE lawyer (
  id SERIAL PRIMARY KEY,
  name VARCHAR NOT NULL UNIQUE,
  name_url VARCHAR check(translate(name_url, 'abcdefghijklmnopqrstuvwxyz-', '') = '') NOT NULL UNIQUE
);

I want to SELECT * FROM lawyer where name_url = "john-doe"

Answer 1

Character literals are put into single quotes:

SELECT * 
FROM lawyer 
where name_url = 'john-doe';

See the manual for details:
https://www.postgresql.org/docs/current/static/sql-syntax-lexical.html#SQL-SYNTAX-CONSTANTS

Answer 2

Looking for exact match:

select column1, column2 from mytable where column2 like 'string';

Pattern Match can be achieved using:(returns stringxx, stringyyy..)

select column1, column2 from mytable where column2 like 'string%';

This will return any column2 that matches string***.

For using OR condition, to compare multiple strings below one can be used:

select column1, column2 from mytable where column2 ~* 'string1|string2';