I have a parents table looks like this
CHILD_ID | PARENT_ID | NAME
1 | Null | Bill
2 | 1 | Jane
3 | 1 | Steve
4 | 2 | Ben
5 | 3 | Andrew
Id like to get a result set like this
Bill
---Jane
------Ben
---Steve
------Andrew
I know I need to do a rank query to rank the levels and a self join but all I can find on the net is CTE recursion
I have done this in Oracle before but not in MS SQL
Bit hacky and can be improved but hopefully it shows the principle...
;with relation (childId, parentId, childName, [level], [orderSequence])
as
(
select childId, parentId, childName, 0, cast(childId as varchar(20))
from @parents
where parentId is null
union all
select p.childId, p.parentId, r.[level]+1, cast(r.orderSequence + '_' + cast(p.childId as varchar) as varchar(20))
from @parents p
inner join relation r on p.parentId = r.childId
)
select right('----------', ([level]*3)) +childName
from relation
order by orderSequence
If however you want to avoid recursion then an alternative approach is to implement a tree table with the relevant tree structure information - see http://www.sqlteam.com/article/more-trees-hierarchies-in-sql for a walk through
declare @pc table(CHILD_ID int, PARENT_ID int, [NAME] varchar(80));
insert into @pc
select 1,NULL,'Bill' union all
select 2,1,'Jane' union all
select 3,1,'Steve' union all
select 4,2,'Ben' union all
select 5,3,'Andrew' union all
select 6,NULL,'Tom' union all
select 7,8,'Dick' union all
select 8,6,'Harry' union all
select 9,3,'Stu' union all
select 10,7,'Joe';
; with r as (
select CHILD_ID, PARENT_ID, [NAME], depth=0, sort=cast(CHILD_ID as varchar(max))
from @pc
where PARENT_ID is null
union all
select pc.CHILD_ID, pc.PARENT_ID, pc.[NAME], depth=r.depth+1, sort=r.sort+cast(pc.CHILD_ID as varchar(30))
from r
inner join @pc pc on r.CHILD_ID=pc.PARENT_ID
where r.depth<32767
)
select tree=replicate('-',r.depth*3)+r.[NAME]
from r
order by sort
option(maxrecursion 32767);
This was a tough one:). I expanded the example to include > 1 tree. Results looking good so far.
WITH DirectReports (ParentUniqId, UniqId, SortID)
AS
(
SELECT e.ParentUniqId, e.UniqId, e.UniqId as SortID
FROM Coding.Coding AS e
WHERE isnull(ParentUniqId ,0)=0
UNION ALL
SELECT e.ParentUniqId, e.UniqId,, d.SortID * 100 + e.UniqId as SortID
FROM Coding.Coding AS e
INNER JOIN DirectReports AS d
ON e.ParentUniqId = d.UniqId
)
SELECT ParentUniqId, Perfix,SortID
FROM DirectReports order by rtrim(SortID) , uniqid
来源:https://stackoverflow.com/questions/9380620/parent-child-hierarchy-tree-view