问题
Django automatically creates an id field as primary key.
Now I need to get the object by this id.
object = Class.objects.filter()
How to write this filter?
回答1:
If you want to get an object, using get()
is more straightforward:
obj = Class.objects.get(pk=this_object_id)
回答2:
I got here for the same problem, but for a different reason:
Class.objects.get(id=1)
This code was raising an ImportError exception. What was confusing me was that the code below executed fine and returned a result set as expected:
Class.objects.all()
Tail of the traceback for the get()
method:
File "django/db/models/loading.py", line 197, in get_models
self._populate()
File "django/db/models/loading.py", line 72, in _populate
self.load_app(app_name, True)
File "django/db/models/loading.py", line 94, in load_app
app_module = import_module(app_name)
File "django/utils/importlib.py", line 35, in import_module
__import__(name)
ImportError: No module named myapp
Reading the code inside Django's loading.py
, I came to the conclusion that my settings.py
had a bad path to my app which contains my Class
model definition. All I had to do was correct the path to the app and the get()
method executed fine.
Here is my settings.py
with the corrected path:
INSTALLED_APPS = (
'django.contrib.contenttypes',
'django.contrib.sessions',
'django.contrib.sites',
# ...
'mywebproject.myapp',
)
All the confusion was caused because I am using Django's ORM as a standalone, so the namespace had to reflect that.
回答3:
You can also do:
obj = ClassModel.get_by_id(object_id)
This works, but there may I'm not sure if it's supported in Django 2.
回答4:
You can use:
objects_all=Class.objects.filter(filter_condition="")
This will return a query set even if it gets one object. If you need exactly one object use:
obj=Class.objects.get(conditon="")
来源:https://stackoverflow.com/questions/4300365/django-database-query-how-to-get-object-by-id