Returning distinct values from foreach loop in PHP?

倖福魔咒の 提交于 2019-12-04 06:08:33

Try with:

$property_types = array();
foreach($search_results_unique as $filter_result){
    if ( in_array($filter_result['property_type'], $property_types) ) {
        continue;
    }
    $property_types[] = $filter_result['property_type'];
    echo $filter_result['property_type'];
}

http://php.net/manual/en/function.array-unique.php

Example:

$input = array("a" => "green", "red", "b" => "green", "blue", "red");
$result = array_unique($input); 
print_r($result);

Array
(
    [a] => green
    [0] => red
    [1] => blue
)

You will need to alter it slightly to check using the property_type part of your array.

I'd use two loops here. One to build an array of distinct property_type fields (you can use code in the loop to check the item doesn't already exist).

Then, use a second loop to step through the array and echo the list of items.

You would have to keep track of already echoed values or build a new unique array of the values of all the $filter_result['property_type']. But that would then require you to iterate over that array once more to actually print. So keeping track would be better.

nax

I was thinking there was some parameter to the in_array() function to get the count of the items found.

But is doesn't exist.

So try with array_unique().

The better way is to duplicate the array before the foreach loop and apply this function.

<?php 

$filter=array();
foreach($search_results as $filter_result)
   $filter[]=$filter_result['property_type'];
$filter=array_unique($filter);

print_r($filter);
?>
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