How to set variable precision for new python format option

问题

I am loving the new format option for strings containing variables, but I would like to have a variable that sets the precision through out my script and I am not sure how to do that. Let me give a small example:

a = 1.23456789
out_str = 'a = {0:.3f}'.format(a)
print(out_str)

Now this is what I would want to do in pseudo code:

a = 1.23456789
some_precision = 5
out_str = 'a = {0:.(some_precision)f}'.format(a)
print(out_str)

but I am not sure, if it is possibly and if it is possibly how the syntax would look like.

回答1:

You can nest placeholders, where the nested placeholders can be used anywhere in the format specification:

out_str = 'a = {0:.{some_precision}f}'.format(a, some_precision=some_precision)

I used a named placeholder there, but you could use numbered slots too:

out_str = 'a = {0:.{1}f}'.format(a, some_precision)

Autonumbering for nested slots (Python 2.7 and up) is supported too; numbering still takes place from left to right:

out_str = 'a = {0:.{}f}'.format(a, some_precision)

Nested slots are filled first; the current implementation allows you to nest placeholders up to 2 levels, so using placeholders in placeholders in placeholders doesn't work:

>>> '{:.{}f}'.format(1.234, 2)
'1.23'
>>> '{:.{:{}}f}'.format(1.234, 2, 'd')
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
ValueError: Max string recursion exceeded

You also can't use placeholders in the field name (so no dynamic allocation of values to slots).

回答2:

Or you can use numbering.

a = 1.23456789
some_precision = 5
out_str = 'a = {0:.{1}f}'.format(a,some_precision)
print(out_str)

Ouptut:

a = 1.23457

来源：https://stackoverflow.com/questions/41853132/how-to-set-variable-precision-for-new-python-format-option