Simplest way to get a PTY in Linux C++

天大地大妈咪最大 提交于 2019-12-04 04:16:59

问题


I am programming something that needs an interface to Bash. At first I thought I could just use popen or QProcess. ( I'm using QT C++ ) They work fine but I can't get them to run Bash in a tty, which you need if you are going to use anything like sudo, which requires a tty/pty to accept a password.

I found some things like forkpty(), openpty(), etc. in the GNU Standard C libraries, but could not figure out how to use them or find any good examples, even after reading their corresponding manpages. Literally, all this part of my program needs to do is be able to read/write from a tty running /bin/bash. Is it really that simple, or is there more to it than meets the eye?

If so, can anyone please provide a concise example on how to do this? Thanks in advance! EDIT: Here's the header file I've come up with!


回答1:


Consider the option of running /bin/sh -s, which means "read commands from standard input". That removes the need to emulate a terminal.



来源:https://stackoverflow.com/questions/2155314/simplest-way-to-get-a-pty-in-linux-c

标签
易学教程内所有资源均来自网络或用户发布的内容,如有违反法律规定的内容欢迎反馈
该文章没有解决你所遇到的问题?点击提问,说说你的问题,让更多的人一起探讨吧!