问题
I need to unzip multiple files at once and add it as a data frame in my R dashboard.
I'm currently using this code:
zipF<- "/Users/sahilverma13/Desktop/chat_data_2017-01-30_IST.zip"
outDir<-"/Users/sahilverma13/Desktop"
unzip(zipF,exdir=outDir)
But I have to do it for every file separately.
zipF <- list.files(pattern="*.zip")
I tried using the wildcard but it doesn't work.
Please help.
回答1:
I often use the ldply function from the plyr package to read or do stuff with multiple files.
library(plyr)
# get all the zip files
zipF <- list.files(path = "/your/path/here/", pattern = "*.zip", full.names = TRUE)
# unzip all your files
ldply(.data = zipF, .fun = unzip, exdir = outDir)
As Richard pointed out this is not complete (to much coffee in the morning is also not good).
# get the csv files
csv_files <- list.files(path = outDir, pattern = "*.csv")
# read the csv files
my_data <- ldply(.data = csv_files, .fun = read.csv)
I liked the comment of Joel a lot. I'am used to using the plyr package so much that I forgot that you can also use the sapply function. Maybe even better to use!
来源：https://stackoverflow.com/questions/41954183/how-can-i-extract-multiple-zip-files-and-read-those-csvs-in-r