问题
I want to get the filename (without extension) and the extension separately.
The best solution I found so far is:
NAME=`echo "$FILE" | cut -d'.' -f1`
EXTENSION=`echo "$FILE" | cut -d'.' -f2`
This is wrong because it doesn't work if the file name contains multiple .
characters. If, let's say, I have a.b.js
, it will consider a
and b.js
, instead of a.b
and js
.
It can be easily done in Python with
file, ext = os.path.splitext(path)
but I'd prefer not to fire up a Python interpreter just for this, if possible.
Any better ideas?
回答1:
First, get file name without the path:
filename=$(basename -- "$fullfile")
extension="${filename##*.}"
filename="${filename%.*}"
Alternatively, you can focus on the last '/' of the path instead of the '.' which should work even if you have unpredictable file extensions:
filename="${fullfile##*/}"
You may want to check the documentation :
- On the web at section "3.5.3 Shell Parameter Expansion"
- In the bash manpage at section called "Parameter Expansion"
回答2:
~% FILE="example.tar.gz"
~% echo "${FILE%%.*}"
example
~% echo "${FILE%.*}"
example.tar
~% echo "${FILE#*.}"
tar.gz
~% echo "${FILE##*.}"
gz
For more details, see shell parameter expansion in the Bash manual.
回答3:
Usually you already know the extension, so you might wish to use:
basename filename .extension
for example:
basename /path/to/dir/filename.txt .txt
and we get
filename
回答4:
You can use the magic of POSIX variables:
bash-3.2$ FILENAME=somefile.tar.gz
bash-3.2$ echo ${FILENAME%%.*}
somefile
bash-3.2$ echo ${FILENAME%.*}
somefile.tar
There's a caveat in that if your filename was of the form ./somefile.tar.gz
then echo ${FILENAME%%.*}
would greedily remove the longest match to the .
and you'd have the empty string.
(You can work around that with a temporary variable:
FULL_FILENAME=$FILENAME
FILENAME=${FULL_FILENAME##*/}
echo ${FILENAME%%.*}
)
This site explains more.
${variable%pattern}
Trim the shortest match from the end
${variable##pattern}
Trim the longest match from the beginning
${variable%%pattern}
Trim the longest match from the end
${variable#pattern}
Trim the shortest match from the beginning
回答5:
That doesn't seem to work if the file has no extension, or no filename. Here is what I'm using; it only uses builtins and handles more (but not all) pathological filenames.
#!/bin/bash
for fullpath in "$@"
do
filename="${fullpath##*/}" # Strip longest match of */ from start
dir="${fullpath:0:${#fullpath} - ${#filename}}" # Substring from 0 thru pos of filename
base="${filename%.[^.]*}" # Strip shortest match of . plus at least one non-dot char from end
ext="${filename:${#base} + 1}" # Substring from len of base thru end
if [[ -z "$base" && -n "$ext" ]]; then # If we have an extension and no base, it's really the base
base=".$ext"
ext=""
fi
echo -e "$fullpath:\n\tdir = \"$dir\"\n\tbase = \"$base\"\n\text = \"$ext\""
done
And here are some testcases:
$ basename-and-extension.sh / /home/me/ /home/me/file /home/me/file.tar /home/me/file.tar.gz /home/me/.hidden /home/me/.hidden.tar /home/me/.. . /: dir = "/" base = "" ext = "" /home/me/: dir = "/home/me/" base = "" ext = "" /home/me/file: dir = "/home/me/" base = "file" ext = "" /home/me/file.tar: dir = "/home/me/" base = "file" ext = "tar" /home/me/file.tar.gz: dir = "/home/me/" base = "file.tar" ext = "gz" /home/me/.hidden: dir = "/home/me/" base = ".hidden" ext = "" /home/me/.hidden.tar: dir = "/home/me/" base = ".hidden" ext = "tar" /home/me/..: dir = "/home/me/" base = ".." ext = "" .: dir = "" base = "." ext = ""
回答6:
You can use basename.
Example:
$ basename foo-bar.tar.gz .tar.gz
foo-bar
You do need to provide basename with the extension that shall be removed, however if you are always executing tar
with -z
then you know the extension will be .tar.gz
.
This should do what you want:
tar -zxvf $1
cd $(basename $1 .tar.gz)
回答7:
pax> echo a.b.js | sed 's/\.[^.]*$//'
a.b
pax> echo a.b.js | sed 's/^.*\.//'
js
works fine, so you can just use:
pax> FILE=a.b.js
pax> NAME=$(echo "$FILE" | sed 's/\.[^.]*$//')
pax> EXTENSION=$(echo "$FILE" | sed 's/^.*\.//')
pax> echo $NAME
a.b
pax> echo $EXTENSION
js
The commands, by the way, work as follows.
The command for NAME
substitutes a "."
character followed by any number of non-"."
characters up to the end of the line, with nothing (i.e., it removes everything from the final "."
to the end of the line, inclusive). This is basically a non-greedy substitution using regex trickery.
The command for EXTENSION
substitutes a any number of characters followed by a "."
character at the start of the line, with nothing (i.e., it removes everything from the start of the line to the final dot, inclusive). This is a greedy substitution which is the default action.
回答8:
Mellen writes in a comment on a blog post:
Using Bash, there’s also ${file%.*}
to get the filename without the extension and ${file##*.}
to get the extension alone. That is,
file="thisfile.txt"
echo "filename: ${file%.*}"
echo "extension: ${file##*.}"
Outputs:
filename: thisfile
extension: txt
回答9:
No need to bother with awk
or sed
or even perl
for this simple task. There is a pure-Bash, os.path.splitext()
-compatible solution which only uses parameter expansions.
Reference Implementation
Documentation of os.path.splitext(path):
Split the pathname path into a pair
(root, ext)
such thatroot + ext == path
, and ext is empty or begins with a period and contains at most one period. Leading periods on the basename are ignored;splitext('.cshrc')
returns('.cshrc', '')
.
Python code:
root, ext = os.path.splitext(path)
Bash Implementation
Honoring leading periods
root="${path%.*}"
ext="${path#"$root"}"
Ignoring leading periods
root="${path#.}";root="${path%"$root"}${root%.*}"
ext="${path#"$root"}"
Tests
Here are test cases for the Ignoring leading periods implementation, which should match the Python reference implementation on every input.
|---------------|-----------|-------|
|path |root |ext |
|---------------|-----------|-------|
|' .txt' |' ' |'.txt' |
|' .txt.txt' |' .txt' |'.txt' |
|' txt' |' txt' |'' |
|'*.txt.txt' |'*.txt' |'.txt' |
|'.cshrc' |'.cshrc' |'' |
|'.txt' |'.txt' |'' |
|'?.txt.txt' |'?.txt' |'.txt' |
|'\n.txt.txt' |'\n.txt' |'.txt' |
|'\t.txt.txt' |'\t.txt' |'.txt' |
|'a b.txt.txt' |'a b.txt' |'.txt' |
|'a*b.txt.txt' |'a*b.txt' |'.txt' |
|'a?b.txt.txt' |'a?b.txt' |'.txt' |
|'a\nb.txt.txt' |'a\nb.txt' |'.txt' |
|'a\tb.txt.txt' |'a\tb.txt' |'.txt' |
|'txt' |'txt' |'' |
|'txt.pdf' |'txt' |'.pdf' |
|'txt.tar.gz' |'txt.tar' |'.gz' |
|'txt.txt' |'txt' |'.txt' |
|---------------|-----------|-------|
Test Results
All tests passed.
回答10:
You could use the cut command to remove the last two extensions (the ".tar.gz"
part):
$ echo "foo.tar.gz" | cut -d'.' --complement -f2-
foo
As noted by Clayton Hughes in a comment, this will not work for the actual example in the question. So as an alternative I propose using sed
with extended regular expressions, like this:
$ echo "mpc-1.0.1.tar.gz" | sed -r 's/\.[[:alnum:]]+\.[[:alnum:]]+$//'
mpc-1.0.1
It works by removing the last two (alpha-numeric) extensions unconditionally.
[Updated again after comment from Anders Lindahl]
回答11:
Here are some alternative suggestions (mostly in awk
), including some advanced use cases, like extracting version numbers for software packages.
f='/path/to/complex/file.1.0.1.tar.gz'
# Filename : 'file.1.0.x.tar.gz'
echo "$f" | awk -F'/' '{print $NF}'
# Extension (last): 'gz'
echo "$f" | awk -F'[.]' '{print $NF}'
# Extension (all) : '1.0.1.tar.gz'
echo "$f" | awk '{sub(/[^.]*[.]/, "", $0)} 1'
# Extension (last-2): 'tar.gz'
echo "$f" | awk -F'[.]' '{print $(NF-1)"."$NF}'
# Basename : 'file'
echo "$f" | awk '{gsub(/.*[/]|[.].*/, "", $0)} 1'
# Basename-extended : 'file.1.0.1.tar'
echo "$f" | awk '{gsub(/.*[/]|[.]{1}[^.]+$/, "", $0)} 1'
# Path : '/path/to/complex/'
echo "$f" | awk '{match($0, /.*[/]/, a); print a[0]}'
# or
echo "$f" | grep -Eo '.*[/]'
# Folder (containing the file) : 'complex'
echo "$f" | awk -F'/' '{$1=""; print $(NF-1)}'
# Version : '1.0.1'
# Defined as 'number.number' or 'number.number.number'
echo "$f" | grep -Eo '[0-9]+[.]+[0-9]+[.]?[0-9]?'
# Version - major : '1'
echo "$f" | grep -Eo '[0-9]+[.]+[0-9]+[.]?[0-9]?' | cut -d. -f1
# Version - minor : '0'
echo "$f" | grep -Eo '[0-9]+[.]+[0-9]+[.]?[0-9]?' | cut -d. -f2
# Version - patch : '1'
echo "$f" | grep -Eo '[0-9]+[.]+[0-9]+[.]?[0-9]?' | cut -d. -f3
# All Components : "path to complex file 1 0 1 tar gz"
echo "$f" | awk -F'[/.]' '{$1=""; print $0}'
# Is absolute : True (exit-code : 0)
# Return true if it is an absolute path (starting with '/' or '~/'
echo "$f" | grep -q '^[/]\|^~/'
All use cases are using the original full path as input, without depending on intermediate results.
回答12:
The accepted answer works well in typical cases, but fails in edge cases, namely:
- For filenames without extension (called suffix in the remainder of this answer),
extension=${filename##*.}
returns the input filename rather than an empty string. extension=${filename##*.}
does not include the initial.
, contrary to convention.- Blindly prepending
.
would not work for filenames without suffix.
- Blindly prepending
filename="${filename%.*}"
will be the empty string, if the input file name starts with.
and contains no further.
characters (e.g.,.bash_profile
) - contrary to convention.
---------
Thus, the complexity of a robust solution that covers all edge cases calls for a function - see its definition below; it can return all components of a path.
Example call:
splitPath '/etc/bash.bashrc' dir fname fnameroot suffix
# -> $dir == '/etc'
# -> $fname == 'bash.bashrc'
# -> $fnameroot == 'bash'
# -> $suffix == '.bashrc'
Note that the arguments after the input path are freely chosen, positional variable names.
To skip variables not of interest that come before those that are, specify _
(to use throw-away variable $_
) or ''
; e.g., to extract filename root and extension only, use splitPath '/etc/bash.bashrc' _ _ fnameroot extension
.
# SYNOPSIS
# splitPath path varDirname [varBasename [varBasenameRoot [varSuffix]]]
# DESCRIPTION
# Splits the specified input path into its components and returns them by assigning
# them to variables with the specified *names*.
# Specify '' or throw-away variable _ to skip earlier variables, if necessary.
# The filename suffix, if any, always starts with '.' - only the *last*
# '.'-prefixed token is reported as the suffix.
# As with `dirname`, varDirname will report '.' (current dir) for input paths
# that are mere filenames, and '/' for the root dir.
# As with `dirname` and `basename`, a trailing '/' in the input path is ignored.
# A '.' as the very first char. of a filename is NOT considered the beginning
# of a filename suffix.
# EXAMPLE
# splitPath '/home/jdoe/readme.txt' parentpath fname fnameroot suffix
# echo "$parentpath" # -> '/home/jdoe'
# echo "$fname" # -> 'readme.txt'
# echo "$fnameroot" # -> 'readme'
# echo "$suffix" # -> '.txt'
# ---
# splitPath '/home/jdoe/readme.txt' _ _ fnameroot
# echo "$fnameroot" # -> 'readme'
splitPath() {
local _sp_dirname= _sp_basename= _sp_basename_root= _sp_suffix=
# simple argument validation
(( $# >= 2 )) || { echo "$FUNCNAME: ERROR: Specify an input path and at least 1 output variable name." >&2; exit 2; }
# extract dirname (parent path) and basename (filename)
_sp_dirname=$(dirname "$1")
_sp_basename=$(basename "$1")
# determine suffix, if any
_sp_suffix=$([[ $_sp_basename = *.* ]] && printf %s ".${_sp_basename##*.}" || printf '')
# determine basename root (filemane w/o suffix)
if [[ "$_sp_basename" == "$_sp_suffix" ]]; then # does filename start with '.'?
_sp_basename_root=$_sp_basename
_sp_suffix=''
else # strip suffix from filename
_sp_basename_root=${_sp_basename%$_sp_suffix}
fi
# assign to output vars.
[[ -n $2 ]] && printf -v "$2" "$_sp_dirname"
[[ -n $3 ]] && printf -v "$3" "$_sp_basename"
[[ -n $4 ]] && printf -v "$4" "$_sp_basename_root"
[[ -n $5 ]] && printf -v "$5" "$_sp_suffix"
return 0
}
test_paths=(
'/etc/bash.bashrc'
'/usr/bin/grep'
'/Users/jdoe/.bash_profile'
'/Library/Application Support/'
'readme.new.txt'
)
for p in "${test_paths[@]}"; do
echo ----- "$p"
parentpath= fname= fnameroot= suffix=
splitPath "$p" parentpath fname fnameroot suffix
for n in parentpath fname fnameroot suffix; do
echo "$n=${!n}"
done
done
Test code that exercises the function:
test_paths=(
'/etc/bash.bashrc'
'/usr/bin/grep'
'/Users/jdoe/.bash_profile'
'/Library/Application Support/'
'readme.new.txt'
)
for p in "${test_paths[@]}"; do
echo ----- "$p"
parentpath= fname= fnameroot= suffix=
splitPath "$p" parentpath fname fnameroot suffix
for n in parentpath fname fnameroot suffix; do
echo "$n=${!n}"
done
done
Expected output - note the edge cases:
- a filename having no suffix
- a filename starting with
.
(not considered the start of the suffix) - an input path ending in
/
(trailing/
is ignored) - an input path that is a filename only (
.
is returned as the parent path) - a filename that has more than
.
-prefixed token (only the last is considered the suffix):
----- /etc/bash.bashrc
parentpath=/etc
fname=bash.bashrc
fnameroot=bash
suffix=.bashrc
----- /usr/bin/grep
parentpath=/usr/bin
fname=grep
fnameroot=grep
suffix=
----- /Users/jdoe/.bash_profile
parentpath=/Users/jdoe
fname=.bash_profile
fnameroot=.bash_profile
suffix=
----- /Library/Application Support/
parentpath=/Library
fname=Application Support
fnameroot=Application Support
suffix=
----- readme.new.txt
parentpath=.
fname=readme.new.txt
fnameroot=readme.new
suffix=.txt
回答13:
Smallest and simplest solution (in single line) is:
$ file=/blaabla/bla/blah/foo.txt
echo $(basename ${file%.*}) # foo
回答14:
I think that if you just need the name of the file, you can try this:
FULLPATH=/usr/share/X11/xorg.conf.d/50-synaptics.conf
# Remove all the prefix until the "/" character
FILENAME=${FULLPATH##*/}
# Remove all the prefix until the "." character
FILEEXTENSION=${FILENAME##*.}
# Remove a suffix, in our case, the filename. This will return the name of the directory that contains this file.
BASEDIRECTORY=${FULLPATH%$FILENAME}
echo "path = $FULLPATH"
echo "file name = $FILENAME"
echo "file extension = $FILEEXTENSION"
echo "base directory = $BASEDIRECTORY"
And that is all =D.
回答15:
You can force cut to display all fields and subsequent ones adding -
to field number.
NAME=`basename "$FILE"`
EXTENSION=`echo "$NAME" | cut -d'.' -f2-`
So if FILE is eth0.pcap.gz
, the EXTENSION will be pcap.gz
Using the same logic, you can also fetch the file name using '-' with cut as follows :
NAME=`basename "$FILE" | cut -d'.' -f-1`
This works even for filenames that do not have any extension.
回答16:
Ok so if I understand correctly, the problem here is how to get the name and the full extension of a file that has multiple extensions, e.g., stuff.tar.gz
.
This works for me:
fullfile="stuff.tar.gz"
fileExt=${fullfile#*.}
fileName=${fullfile%*.$fileExt}
This will give you stuff
as filename and .tar.gz
as extension. It works for any number of extensions, including 0. Hope this helps for anyone having the same problem =)
回答17:
Magic file recognition
In addition to the lot of good answers on this Stack Overflow question I would like to add:
Under Linux and other unixen, there is a magic command named file
, that do filetype detection by analysing some first bytes of file. This is a very old tool, initialy used for print servers (if not created for... I'm not sure about that).
file myfile.txt
myfile.txt: UTF-8 Unicode text
file -b --mime-type myfile.txt
text/plain
Standards extensions could be found in /etc/mime.types
(on my Debian GNU/Linux desktop. See man file
and man mime.types
. Perhaps you have to install the file
utility and mime-support
packages):
grep $( file -b --mime-type myfile.txt ) </etc/mime.types
text/plain asc txt text pot brf srt
You could create a bash function for determining right extension. There is a little (not perfect) sample:
file2ext() {
local _mimetype=$(file -Lb --mime-type "$1") _line _basemimetype
case ${_mimetype##*[/.-]} in
gzip | bzip2 | xz | z )
_mimetype=${_mimetype##*[/.-]}
_mimetype=${_mimetype//ip}
_basemimetype=$(file -zLb --mime-type "$1")
;;
stream )
_mimetype=($(file -Lb "$1"))
[ "${_mimetype[1]}" = "compressed" ] &&
_basemimetype=$(file -b --mime-type - < <(
${_mimetype,,} -d <"$1")) ||
_basemimetype=${_mimetype,,}
_mimetype=${_mimetype,,}
;;
executable ) _mimetype='' _basemimetype='' ;;
dosexec ) _mimetype='' _basemimetype='exe' ;;
shellscript ) _mimetype='' _basemimetype='sh' ;;
* )
_basemimetype=$_mimetype
_mimetype=''
;;
esac
while read -a _line ;do
if [ "$_line" == "$_basemimetype" ] ;then
[ "$_line[1]" ] &&
_basemimetype=${_line[1]} ||
_basemimetype=${_basemimetype##*[/.-]}
break
fi
done </etc/mime.types
case ${_basemimetype##*[/.-]} in
executable ) _basemimetype='' ;;
shellscript ) _basemimetype='sh' ;;
dosexec ) _basemimetype='exe' ;;
* ) ;;
esac
[ "$_mimetype" ] && [ "$_basemimetype" != "$_mimetype" ] &&
printf ${2+-v} $2 "%s.%s" ${_basemimetype##*[/.-]} ${_mimetype##*[/.-]} ||
printf ${2+-v} $2 "%s" ${_basemimetype##*[/.-]}
}
This function could set a Bash variable that can be used later:
(This is inspired from @Petesh right answer):
filename=$(basename "$fullfile")
filename="${filename%.*}"
file2ext "$fullfile" extension
echo "$fullfile -> $filename . $extension"
回答18:
I use the following script
$ echo "foo.tar.gz"|rev|cut -d"." -f3-|rev
foo
回答19:
$ F = "text file.test.txt"
$ echo ${F/*./}
txt
This caters for multiple dots and spaces in a filename, however if there is no extension it returns the filename itself. Easy to check for though; just test for the filename and extension being the same.
Naturally this method doesn't work for .tar.gz files. However that could be handled in a two step process. If the extension is gz then check again to see if there is also a tar extension.
回答20:
How to extract the filename and extension in fish:
function split-filename-extension --description "Prints the filename and extension"
for file in $argv
if test -f $file
set --local extension (echo $file | awk -F. '{print $NF}')
set --local filename (basename $file .$extension)
echo "$filename $extension"
else
echo "$file is not a valid file"
end
end
end
Caveats: Splits on the last dot, which works well for filenames with dots in them, but not well for extensions with dots in them. See example below.
Usage:
$ split-filename-extension foo-0.4.2.zip bar.tar.gz
foo-0.4.2 zip # Looks good!
bar.tar gz # Careful, you probably want .tar.gz as the extension.
There's probably better ways to do this. Feel free to edit my answer to improve it.
If there's a limited set of extensions you'll be dealing with and you know all of them, try this:
switch $file
case *.tar
echo (basename $file .tar) tar
case *.tar.bz2
echo (basename $file .tar.bz2) tar.bz2
case *.tar.gz
echo (basename $file .tar.gz) tar.gz
# and so on
end
This does not have the caveat as the first example, but you do have to handle every case so it could be more tedious depending on how many extensions you can expect.
回答21:
Here is code with AWK. It can be done more simply. But I am not good in AWK.
filename$ ls
abc.a.txt a.b.c.txt pp-kk.txt
filename$ find . -type f | awk -F/ '{print $2}' | rev | awk -F"." '{$1="";print}' | rev | awk 'gsub(" ",".") ,sub(".$", "")'
abc.a
a.b.c
pp-kk
filename$ find . -type f | awk -F/ '{print $2}' | awk -F"." '{print $NF}'
txt
txt
txt
回答22:
Simply use ${parameter%word}
In your case:
${FILE%.*}
If you want to test it, all following work, and just remove the extension:
FILE=abc.xyz; echo ${FILE%.*};
FILE=123.abc.xyz; echo ${FILE%.*};
FILE=abc; echo ${FILE%.*};
回答23:
Building from Petesh answer, if only the filename is needed, both path and extension can be stripped in a single line,
filename=$(basename ${fullname%.*})
回答24:
Based largely off of @mklement0's excellent, and chock-full of random, useful bashisms - as well as other answers to this / other questions / "that darn internet"... I wrapped it all up in a little, slightly more comprehensible, reusable function for my (or your) .bash_profile
that takes care of what (I consider) should be a more robust version of dirname
/basename
/ what have you..
function path { SAVEIFS=$IFS; IFS="" # stash IFS for safe-keeping, etc.
[[ $# != 2 ]] && echo "usage: path <path> <dir|name|fullname|ext>" && return # demand 2 arguments
[[ $1 =~ ^(.*/)?(.+)?$ ]] && { # regex parse the path
dir=${BASH_REMATCH[1]}
file=${BASH_REMATCH[2]}
ext=$([[ $file = *.* ]] && printf %s ${file##*.} || printf '')
# edge cases for extensionless files and files like ".nesh_profile.coffee"
[[ $file == $ext ]] && fnr=$file && ext='' || fnr=${file:0:$((${#file}-${#ext}))}
case "$2" in
dir) echo "${dir%/*}"; ;;
name) echo "${fnr%.*}"; ;;
fullname) echo "${fnr%.*}.$ext"; ;;
ext) echo "$ext"; ;;
esac
}
IFS=$SAVEIFS
}
Usage examples...
SOMEPATH=/path/to.some/.random\ file.gzip
path $SOMEPATH dir # /path/to.some
path $SOMEPATH name # .random file
path $SOMEPATH ext # gzip
path $SOMEPATH fullname # .random file.gzip
path gobbledygook # usage: -bash <path> <dir|name|fullname|ext>
回答25:
A simple answer:
To expand on the POSIX variables answer, note that you can do more interesting patterns. So for the case detailed here, you could simply do this:
tar -zxvf $1
cd ${1%.tar.*}
That will cut off the last occurrence of .tar.<something>.
More generally, if you wanted to remove the last occurrence of .<something>.<something-else> then
${1.*.*}
should work fine.
The link the above answer appears to be dead. Here's a great explanation of a bunch of the string manipulation you can do directly in Bash, from TLDP.
回答26:
If you also want to allow empty extensions, this is the shortest I could come up with:
echo 'hello.txt' | sed -r 's/.+\.(.+)|.*/\1/' # EXTENSION
echo 'hello.txt' | sed -r 's/(.+)\..+|(.*)/\1\2/' # FILENAME
1st line explained: It matches PATH.EXT or ANYTHING and replaces it with EXT. If ANYTHING was matched, the ext group is not captured.
回答27:
Using example file /Users/Jonathan/Scripts/bash/MyScript.sh
, this code:
MY_EXT=".${0##*.}"
ME=$(/usr/bin/basename "${0}" "${MY_EXT}")
will result in ${ME}
being MyScript
and ${MY_EXT}
being .sh
:
Script:
#!/bin/bash
set -e
MY_EXT=".${0##*.}"
ME=$(/usr/bin/basename "${0}" "${MY_EXT}")
echo "${ME} - ${MY_EXT}"
Some tests:
$ ./MyScript.sh
MyScript - .sh
$ bash MyScript.sh
MyScript - .sh
$ /Users/Jonathan/Scripts/bash/MyScript.sh
MyScript - .sh
$ bash /Users/Jonathan/Scripts/bash/MyScript.sh
MyScript - .sh
回答28:
From the answers above, the shortest oneliner to mimic Python's
file, ext = os.path.splitext(path)
presuming your file really does have an extension, is
EXT="${PATH##*.}"; FILE=$(basename "$PATH" .$EXT)
回答29:
IMHO the best solution has already been given (using shell parameter expansion) and are the best rated one at this time.
I however add this one which just use dumbs commands, which is not efficient and which noone serious should use ever :
FILENAME=$(echo $FILE | cut -d . -f 1-$(printf $FILE | tr . '\n' | wc -l))
EXTENSION=$(echo $FILE | tr . '\n' | tail -1)
Added just for fun :-)
回答30:
This is the only one that worked for me:
path='folder/other_folder/file.js'
base=${path##*/}
echo ${base%.*}
>> file
This can also be used in string interpolation as well, but unfortunately you have to set base
beforehand.
来源:https://stackoverflow.com/questions/14703318/bash-script-remove-extension-from-file-name