Change color of UISwitch in “off” state

冷暖自知 提交于 2019-11-26 18:58:41

问题


I've learned that we can change the UISwitch button appearance in its "on" state, but is it also possible to change the color of the UISwitch in the "off" state?


回答1:


Try using this

yourSwitch.backgroundColor = [UIColor whiteColor];
youSwitch.layer.cornerRadius = 16.0;

All thanks to @Barry Wyckoff.




回答2:


My solution with #swift2:

let onColor  = _your_on_state_color
let offColor = _your_off_state_color

let mSwitch = UISwitch(frame: CGRectZero)
mSwitch.on = true

/*For on state*/
mSwitch.onTintColor = onColor

/*For off state*/
mSwitch.tintColor = offColor
mSwitch.layer.cornerRadius = mSwitch.frame.height / 2
mSwitch.backgroundColor = offColor

Result:




回答3:


You can use the tintColor property on the switch.

switch.tintColor = [UIColor redColor]; // the "off" color
switch.onTintColor = [UIColor greenColor]; // the "on" color

Note this requires iOS 5+




回答4:


Swift IBDesignable

import UIKit
@IBDesignable

class UISwitchCustom: UISwitch {
    @IBInspectable var OffTint: UIColor? {
        didSet {
            self.tintColor = OffTint
            self.layer.cornerRadius = 16
            self.backgroundColor = OffTint
        }
    }
}

set class in Identity inspector

change color from Attributes inspector

Output




回答5:


The Best way to manage background color & size of UISwitch

For now it's Swift 2.3 code

import Foundation
import UIKit

@IBDesignable
class UICustomSwitch : UISwitch {

    @IBInspectable var OnColor : UIColor! = UIColor.blueColor()
    @IBInspectable var OffColor : UIColor! = UIColor.grayColor()
    @IBInspectable var Scale : CGFloat! = 1.0

    override init(frame: CGRect) {
        super.init(frame: frame)
        self.setUpCustomUserInterface()
    }

    required init?(coder aDecoder: NSCoder) {
        super.init(coder: aDecoder)
        self.setUpCustomUserInterface()
    }


    func setUpCustomUserInterface() {

        //clip the background color
        self.layer.cornerRadius = 16
        self.layer.masksToBounds = true

        //Scale down to make it smaller in look
        self.transform = CGAffineTransformMakeScale(self.Scale, self.Scale);

        //add target to get user interation to update user-interface accordingly
        self.addTarget(self, action: #selector(UICustomSwitch.updateUI), forControlEvents: UIControlEvents.ValueChanged)

        //set onTintColor : is necessary to make it colored
        self.onTintColor = self.OnColor

        //setup to initial state
        self.updateUI()
    }

    //to track programatic update
    override func setOn(on: Bool, animated: Bool) {
        super.setOn(on, animated: true)
        updateUI()
    }

    //Update user-interface according to on/off state
    func updateUI() {
        if self.on == true {
            self.backgroundColor = self.OnColor
        }
        else {
            self.backgroundColor = self.OffColor
        }
    }
}



回答6:


In Swift 4+:

off state:

switch.tintColor = UIColor.blue

on state:

switch.onTintColor = UIColor.red



回答7:


Here's a pretty good trick: you can just reach right into the UISwitch's subview that draws its "off" background, and change its background color. This works a lot better in iOS 13 than it does in iOS 12:

if #available(iOS 13.0, *) {
    self.sw.subviews[0].subviews[0].backgroundColor = .green
} else if #available(iOS 12.0, *) {
    self.sw.subviews[0].subviews[0].subviews[0].backgroundColor = .green
}



回答8:


Swift 4 easiest and fastest way to get it in 3 steps:

// background color is the color of the background of the switch
switchControl.backgroundColor = UIColor.white.withAlphaComponent(0.9)

// tint color is the color of the border when the switch is off, use
// clear if you want it the same as the background, or different otherwise
switchControl.tintColor = UIColor.clear

// and make sure that the background color will stay in border of the switch
switchControl.layer.cornerRadius = switchControl.bounds.height / 2

If you manually change the size of the switch (e.g., by using autolayout), you will have to update the switch.layer.cornerRadius too, e.g., by overriding layoutSubviews and after calling super updating the corner radius:

override func layoutSubviews() {
    super.layoutSubviews()
    switchControl.layer.cornerRadius = switchControl.bounds.height / 2
}



回答9:


The UISwitch offTintColor is transparent, so whatever is behind the switch shows through. Therefore, instead of masking the background color, it suffices to draw a switch-shaped image behind the switch (this implementation assumes that the switch is positioned by autolayout):

func putColor(_ color: UIColor, behindSwitch sw: UISwitch) {
    guard sw.superview != nil else {return}
    let onswitch = UISwitch()
    onswitch.isOn = true
    let r = UIGraphicsImageRenderer(bounds:sw.bounds)
    let im = r.image { ctx in
        onswitch.layer.render(in: ctx.cgContext)
        }.withRenderingMode(.alwaysTemplate)
    let iv = UIImageView(image:im)
    iv.tintColor = color
    sw.superview!.insertSubview(iv, belowSubview: sw)
    iv.translatesAutoresizingMaskIntoConstraints = false
    NSLayoutConstraint.activate([
        iv.topAnchor.constraint(equalTo: sw.topAnchor),
        iv.bottomAnchor.constraint(equalTo: sw.bottomAnchor),
        iv.leadingAnchor.constraint(equalTo: sw.leadingAnchor),
        iv.trailingAnchor.constraint(equalTo: sw.trailingAnchor),
    ])
}

[But see now my other answer.]




回答10:


Swift 5:

import UIKit

extension UISwitch {    

    func set(offTint color: UIColor ) {
        let minSide = min(bounds.size.height, bounds.size.width)
        layer.cornerRadius = minSide / 2
        backgroundColor = color
        tintColor = color
    }
}



回答11:


Should you need other switches around your app, it might be also a good idea implementing @LongPham's code inside a custom class. As others have pointed out, for the "off" state you'll need to change the background colour as well, since the default is transparent.

class MySwitch: UISwitch {

  required init?(coder aDecoder: NSCoder) {
    super.init(coder: aDecoder)

    // Setting "on" state colour
    self.onTintColor        = UIColor.green

    // Setting "off" state colour
    self.tintColor          = UIColor.red
    self.layer.cornerRadius = self.frame.height / 2
    self.backgroundColor    = UIColor.red
  }
}



回答12:


More safe way in Swift 3 without magical 16pt values:

class ColoredBackgroundSwitch: UISwitch {

  var offTintColor: UIColor {
    get {
      return backgroundColor ?? UIColor.clear
    }
    set {
      backgroundColor = newValue
    }
  }

  override func layoutSubviews() {
    super.layoutSubviews()
    let minSide = min(frame.size.height, frame.size.width)
    layer.cornerRadius = ceil(minSide / 2)
  }

}



回答13:


objective c category to use on any UISlider in project using code or storyboard:

#import <UIKit/UIKit.h>

@interface UISwitch (SAHelper)
@property (nonatomic) IBInspectable UIColor *offTint;
@end

implementation

#import "UISwitch+SAHelper.h"

@implementation UISwitch (SAHelper)
@dynamic offTint;
- (void)setOffTint:(UIColor *)offTint {
    self.tintColor = offTint;   //comment this line to hide border in off state
    self.layer.cornerRadius = 16;
    self.backgroundColor = offTint;
}
@end



回答14:


XCode 11, Swift 4.2

Starting with Matt's solution I added it to a custom, IBDesignable control. There is a timing issue in that didMoveToSuperview() is called before the offTintColor is set that needed to be handled.

@IBDesignable public class UISwitchCustom: UISwitch {

    var switchMask: UIImageView?
    private var observers = [NSKeyValueObservation]()

    @IBInspectable dynamic var offTintColor : UIColor! = UIColor.gray {
        didSet {
             switchMask?.tintColor = offTintColor
        }
    }

    override init(frame: CGRect) {
        super.init(frame: frame)
        initializeObservers()
    }

    required init?(coder aDecoder: NSCoder) {
        super.init(coder: aDecoder)
        initializeObservers()
    }

    private func initializeObservers() {
        observers.append(observe(\.isHidden, options: [.initial]) {(model, change) in
            self.switchMask?.isHidden = self.isHidden
        })
    }

    override public func didMoveToSuperview() {
        addOffColorMask(offTintColor)
        super.didMoveToSuperview()
    }

   private func addOffColorMask(_ color: UIColor) {
        guard self.superview != nil else {return}
        let onswitch = UISwitch()
        onswitch.isOn = true
        let r = UIGraphicsImageRenderer(bounds:self.bounds)
        let im = r.image { ctx in
            onswitch.layer.render(in: ctx.cgContext)
            }.withRenderingMode(.alwaysTemplate)
        let iv = UIImageView(image:im)
        iv.tintColor = color
        self.superview!.insertSubview(iv, belowSubview: self)
        iv.translatesAutoresizingMaskIntoConstraints = false
        NSLayoutConstraint.activate([
            iv.topAnchor.constraint(equalTo: self.topAnchor),
            iv.bottomAnchor.constraint(equalTo: self.bottomAnchor),
            iv.leadingAnchor.constraint(equalTo: self.leadingAnchor),
            iv.trailingAnchor.constraint(equalTo: self.trailingAnchor),
            ])
        switchMask = iv
        switchMask?.isHidden = self.isHidden
    }

}


来源:https://stackoverflow.com/questions/10348869/change-color-of-uiswitch-in-off-state

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