Haskell - defining a function with guards inside a 'where'

拜拜、爱过 提交于 2019-12-03 23:20:31
lowestDivisor :: Integer -> Integer
lowestDivisor n = lowestDivisorHelper 2 n where 
  lowestDivisorHelper m n
        | (m `divides` n) = m  -- these should belong to lowestDivisorHelper
        | otherwise = lowestDivisorHelper (m+1) n

You need to start a new statement with your helper function for the guards to be sufficiently indented by comparison. (And you also forgot an argument, n.) This would also work:

lowestDivisor :: Integer -> Integer
lowestDivisor n = lowestDivisorHelper 2 n 
    where 
  lowestDivisorHelper m n
        | (m `divides` n) = m  -- these should belong to lowestDivisorHelper
        | otherwise = lowestDivisorHelper (m+1) n

but this doesn't:

lowestDivisor :: Integer -> Integer
lowestDivisor n = lowestDivisorHelper 2 n 
  where lowestDivisorHelper m n
        | (m `divides` n) = m  -- these should belong to lowestDivisorHelper
        | otherwise = lowestDivisorHelper (m+1) n

The key point is that the | has to be further to the right than the function name.

In general, starting a new line continues the previous one as long as it is further to the right. The guards have to continue on from the function name.

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