I have
<h:form>
<h:commandLink action="#{my_fake_ajax_link}">
<h:outputText value="Link" />
<f:ajax render=":mydiv" />
</h:commandLink>
</h:form>
<h:panelGroup layout="block" id="mydiv">
<h:form>
<h:commandLink action="#{mybean.delete(0)}">
<h:outputText value="Here" />
<f:ajax render="@form" />
</h:commandLink>
</h:form>
</h:panelGroup>
When I click once on "my_fake_ajax_link", then I have to click twice on "delete" link. This is only an example. I don't have this real case. I have multiple forms on a page and I can't just add all of them in a single form.
I checked what the problem is and it is:
- When you click on "my_fake_ajax_link", the
mydiv
refreshs with ajax as it should. - ViewState of the refreshed form on ajax is missing.
How can I add the ViewState? How can I make it work without using only one form? This looks like an JSF bug to me. I don't want to refresh that div automatically with
jQuery("#mydiv").load(document.location.href);
but I will in my worst case possible.
This is a known problem in the auto-included jsf.js
library of JSF which handles ajax responses. See also JSF spec issue 790 which is fixed in the upcoming JSF 2.3. In the meanwhile, with JSF 2.0/2.1/2.2, you have to explicitly specify the ID of the other <h:form>
inside the render
attribtue to trigger proper addition of the view state.
<h:form>
<h:commandLink action="#{my_fake_ajax_link}">
<h:outputText value="Link" />
<f:ajax render=":mydiv :mydivForm" />
</h:commandLink>
</h:form>
<h:panelGroup layout="block" id="mydiv">
<h:form id="mydivForm">
<h:commandLink action="#{mybean.delete(0)}">
<h:outputText value="Here" />
<f:ajax render="@form" />
</h:commandLink>
</h:form>
</h:panelGroup>
No, this does not cause any overhead or markup duplication in the ajax response. Alternatively, use OmniFaces fixviewstate.js
.
See also:
Workaround for that:
First you need to set an onevent
handler for the button that sends the ajax request:
<h:form id="newComment">
<h:commandButton id="saveNewComment" action="#{postBean.actionSaveNewCommentAjax}" value="#{rb['speichern']}">
<f:ajax execute="@form" render=":commentsBox" onevent="function(data) { fixOtherFormsViewState(data, 'newComment') }" />
</h:commandButton>
</h:form>
Then you need to declare this javascript methods that will take the correct viewState value and add it to all forms which doesn't have it:
<h:outputScript>
function fixOtherFormsViewState(data, goodFormId) {
if (data.status != "success") {
return;
}
var viewState = jQuery("#" + goodFormId + " input[name='javax.faces.ViewState']").val();
jQuery("form:not(:contains(input[name='javax.faces.ViewState']))").each(function (idx, elem) {
var form = jQuery(elem);
var input = jQuery("<input type='hidden' name='javax.faces.ViewState' />").val(viewState);
form.append(input);
});
}
</h:outputScript>
来源:https://stackoverflow.com/questions/7807334/rendering-other-form-by-ajax-causes-its-view-state-to-be-lost-how-do-i-add-this