问题
The man page for xcodebuild reads:
Run xcodebuild from the directory containing your project (i.e. the directory containing the projectname.xcodeproj package).
I would like to keep my source directory (which is a Subversion external) clean and unmodified, and build my object files and executables to a location completely outside of the source directory.
Is there any way to build into a separate build directory from a terminal using xcodebuild like you can do with make tools or even msbuild on Windows?
回答1:
You can set build settings from the command line. The CONFIGURATION_BUILD_DIR will set the build directory. For example:
xcodebuild -project YourProject.xcodeproj -configuration Debug -target All ARCHS=x86_64 ONLY_ACTIVE_ARCH=YES CONFIGURATION_BUILD_DIR=../some/other/dir
A reference is found on Apple's site:
- Build Setting Reference
回答2:
To achieve complete separation the following build settings have to be changed (more than just CONFIGURATION_BUILD_DIR like accepted answer suggests), otherwise Xcode still builds some of its artifacts under its default build folder.
On my machine Xcode normally builds everything to ./Build and ./DerivedData where current directory is one of my project.
I wanted xcodebuild to build everything under Build-command-line folder so I used xcodebuild -scheme MyScheme -showBuildSettings | grep Build\/ to find all build settings that correspond to all build paths and by trial-end-error I found "the generative" build settings that are enough to redirect all build artefacts produced by xcodebuild to custom folder.
I ended up using the following command:
BUILD_DIR=./Build-command-line
DERIVED_DATA_DIR=$(BUILD_DIR)/DerivedData
xcodebuild -project MyProject.xcodeproj \
-IDEBuildOperationMaxNumberOfConcurrentCompileTasks=`sysctl -n hw.ncpu` \
-scheme MyScheme \
-sdk iphonesimulator \
-destination 'platform=iOS Simulator,name=iPhone 6S Plus,OS=latest' \
-xcconfig command-line-build.xcconfig \
-derivedDataPath $(DERIVED_DATA_DIR) \
test
Where command-line-build.xcconfig is:
HERE_BUILD=$(SRCROOT)/Build-command-line
HERE_INTERMEDIATES=$(HERE_BUILD)/Intermediates
// Paths
// the following paths are enough to redirect everything to $HERE_BUILD
MODULE_CACHE_DIR = $(HERE_BUILD)/DerivedData/ModuleCache
OBJROOT = $(HERE_INTERMEDIATES)
SHARED_PRECOMPS_DIR = $(HERE_INTERMEDIATES)/PrecompiledHeaders
SYMROOT
Note: Make sure you use absolute paths in your xcconfig, otherwise you may have error: Xcode crashing on startup “parentPath must be nil but it is not.
I have written a post about this solution with a bit of background: xcodebuild: how to really change its build path.
P.S. Of course this information is subject to change but as of Xcode Version 7.3.1 (7D1014) it works perfectly for me.
回答3:
In my project, setting SYMROOT turned out to be sufficient to build the project in a different location, leaving other locations untouched.
From Apple's Xcode Build Setting Reference (which I came across via another answer here, thanks!):
SYMROOT (Build Products Path)
Description: Directory path. Identifies the root of the directory hierarchy that contains product files and intermediate build files. Product and build files are placed in subdirectories of this directory.
...
Affects: BUILT_PRODUCTS_DIR, CONFIGURATION_BUILD_DIR (...)
This setting is also mentioned a few times in the xcodebuild man page:
Available actions are:
build: Build the target in the build root (SYMROOT)...
clean: Remove build products and intermediate files from the build root (SYMROOT)....
回答4:
Xcode 10
For a Workspace if you're using CocoaPods:
xcodebuild -workspace youProject.xcworkspace -scheme yourScheme -sdk iphonesimulator -configuration Release SYMROOT=$(PWD)/build
That will put your .app in ./build/Release-iphonesimulator
回答5:
You should set the SYMROOT build setting to your desired location. All of the other relevant build settings are derived from it.
来源：https://stackoverflow.com/questions/4969932/separate-build-directory-using-xcodebuild