PHP - Find a string in file then show it's line number

问题

I have an application which needs to open the file, then find string in it, and print a line number where is string found.

For example, file example.txt contains few hashes:

APLF2J51 1a79a4d60de6718e8e5b326e338ae533
EEQJE2YX 66b375b08fc869632935c9e6a9c7f8da O87IGF8R
c458fb5edb84c54f4dc42804622aa0c5 APLF2J51
B7TSW1ZE 1e9eea56686511e9052e6578b56ae018
EEQJE2YX affb23b07576b88d1e9fea50719fb3b7

So, I want to PHP search for "1e9eea56686511e9052e6578b56ae018" and print out its line number, in this case 4.

Please note that there are will not be multiple hashes in file.

I found a few codes over Internet, but none seem to work.

I tried this one:

<?PHP
$string = "1e9eea56686511e9052e6578b56ae018"; 
$data   = file_get_contents("example.txt"); 
$data   = explode("\n", $data); 
for ($line = 0; $line < count($data); $line++) { 
if (strpos($data[$line], $string) >= 0) { 
die("String $string found at line number: $line"); 
} 
} 
?>

It just says that string is found at line 0.... Which is not correct....

Final application is much more complex than that... After it founds line number, it should replace string which something else, and save changes to file, then goes further processing....

Thanks in advance :)

回答1:

An ultra-basic solution could be:

$search      = "1e9eea56686511e9052e6578b56ae018";
$lines       = file('example.txt');
$line_number = false;

while (list($key, $line) = each($lines) and !$line_number) {
   $line_number = (strpos($line, $search) !== FALSE) ? $key + 1 : $line_number;
}

echo $line_number;

A memory-saver version, for larger files:

$search      = "1e9eea56686511e9052e6578b56ae018";
$line_number = false;

if ($handle = fopen("example.txt", "r")) {
   $count = 0;
   while (($line = fgets($handle, 4096)) !== FALSE and !$line_number) {
      $count++;
      $line_number = (strpos($line, $search) !== FALSE) ? $count : $line_number;
   }
   fclose($handle);
}

echo $line_number;

回答2:

function get_line_from_hashes($file, $find){
    $file_content = file_get_contents($file);
    $lines = explode("\n", $file_content);

    foreach($lines as $num => $line){
        $pos = strpos($line, $find);
        if($pos !== false)
            return $num + 1
    }
    return false
}

get_line_from_hashes("arquivo.txt", "asdsadas2e3xe3ceQ@E"); //return some number or false case not found.

回答3:

If you need fast and universal solution that working also for finding line number of multiline text in file, use this:

$file_content = file_get_contents('example.txt');

$content_before_string = strstr($file_content, $string, true);

if (false !== $content_before_string) {
    $line = count(explode(PHP_EOL, $content_before_string));
    die("String $string found at line number: $line");
}

FYI Works only with PHP 5.3.0+.

回答4:

$pattern = '/1e9eea56686511e9052e6578b56ae018/';
if (preg_match($pattern, $content, $matches, PREG_OFFSET_CAPTURE)) {
    //PREG_OFFSET_CAPTURE will add offset of the found string to the array of matches
    //now get a substring of the offset length and explode it by \n
    $lineNumber = count(explode("\n", substr($content, 0, $matches[0][1])));
}

来源：https://stackoverflow.com/questions/19760564/php-find-a-string-in-file-then-show-its-line-number

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php

string

numbers

find

line