问题
Herer is my CRONTAB file (Ubuntu 10.10):
57 1 * * 2-6 ET=`date --date 'yesterday'+%Y%m%d`;echo $ET
Even The syntax color indicate that something is wrong. and there is this error:
Subject: Cron <root> ET=`date --date 'yesterday' + (failed)
Content-Type: text/plain; charset=ANSI_X3.4-1968
X-Cron-Env: <SHELL=/bin/sh>
X-Cron-Env: <HOME=/root>
X-Cron-Env: <PATH=/usr/bin:/bin>
X-Cron-Env: <LOGNAME=root>
/bin/sh: Syntax error: EOF in backquote substitution
But I am not sure whats wrong. Thanks a lot!
回答1:
Cron needs to escape the % sign - http://www.hcidata.info/crontab.htm
Try it with a backslash:
57 1 * * 2-6 ET=`date --date 'yesterday' +\%Y\%m\%d`;echo $ET
来源：https://stackoverflow.com/questions/7068759/crontab-syntax-error