问题
I can perform the following SQL Server selection of distinct (or non-repeating names) from a column in one table like so:
SELECT COUNT(DISTINCT [Name]) FROM [MyTable]
But what if I have more than one table (all these tables contain the name field called [Name]) and I need to know the count of non-repeating names in two or more tables.
If I run something like this:
SELECT COUNT(DISTINCT [Name]) FROM [MyTable1], [MyTable2], [MyTable3]
I get an error, "Ambiguous column name 'Name'".
PS. All three tables [MyTable1], [MyTable2], [MyTable3] are a product of a previous selection.
回答1:
After the clarification, use:
SELECT x.name, COUNT(x.[name])
FROM (SELECT [name]
FROM [MyTable]
UNION ALL
SELECT [name]
FROM [MyTable2]
UNION ALL
SELECT [name]
FROM [MyTable3]) x
GROUP BY x.name
If I understand correctly, use:
SELECT x.name, COUNT(DISTINCT x.[name])
FROM (SELECT [name]
FROM [MyTable]
UNION ALL
SELECT [name]
FROM [MyTable2]
UNION ALL
SELECT [name]
FROM [MyTable3]) x
GROUP BY x.name
UNION
will remove duplicates; UNION ALL
will not, and is faster for it.
回答2:
EDIT: Had to change after seeing recent comment.
Does this give you what you want? This gives a count for each person after combining the rows from all tables.
SELECT [NAME], COUNT(*) as TheCount
FROM
(
SELECT [Name] FROM [MyTable1]
UNION ALL
SELECT [Name] FROM [MyTable2]
UNION ALL
SELECT [Name] FROM [MyTable3]
) AS [TheNames]
GROUP BY [NAME]
回答3:
Here's another way:
SELECT x.name, SUM(x.cnt)
FROM ( SELECT [name], COUNT(*) AS cnt
FROM [MyTable]
GROUP BY [name]
UNION ALL
SELECT [name], COUNT(*) AS cnt
FROM [MyTable2]
GROUP BY [name]
UNION ALL
SELECT [name], COUNT(*) AS cnt
FROM [MyTable3]
GROUP BY [name]
) AS x
GROUP BY x.name
来源:https://stackoverflow.com/questions/6712127/select-countdistinct-name-from-several-tables