static counter in c++

女生的网名这么多〃 提交于 2019-12-03 12:49:30

This:

class Data
{
private:
   static int ID;
   const int currentID;
public:
   Data() : currentID(ID++){
   }
};

Besides a static counter, you also need an instance-bound member.

If the ID is static, then it will have the same value for all class instances.

If you want each instance to have sequential id values, then you could combine the static attribute with a class variable, like this:

class Data
{
private:
   static int ID;
   int thisId;
public:
   Data(){
   thisId = ++ID;
   }
};

int Data::ID = 0;

If the application will be multi threaded, then you'll have to synchronize it with something like a pthread mutex.

Initialization of static variable within a function is allowed so a solution can be something like this

 class Data
 {
    private:
    static int ID ()
    {
       static int ID = 0;
       return ID ++;
    }
    int myId;

    public:
    Data(): myId (ID ())
    {      
    }
 };

Each instance of Data needs its own non-static member variable that stores its ID. A static variable can be used to store the last used ID which would be incremented in the constructor of Data.

Instead of a static counter, which is not thread-safe, consider using boost's uuid:

#include <boost/lexical_cast.hpp>
#include <boost/uuid/uuid.hpp>
#include <boost/uuid/uuid_generators.hpp>
#include <boost/uuid/uuid_io.hpp>

using boost::lexical_cast;
using boost::uuids::uuid;
using boost::uuids::random_generator;

std::string id_ = lexical_cast<std::string>((random_generator())());

where is the instance(non static) id here? you need to declare a new instance ID field like this

int m_ID;

then in your constructor do

Data(){m_ID = ::InterlockedIncrement(&ID);}

in an interlocked or other thread-safe way

易学教程内所有资源均来自网络或用户发布的内容,如有违反法律规定的内容欢迎反馈
该文章没有解决你所遇到的问题?点击提问,说说你的问题,让更多的人一起探讨吧!