Difference between associated and raw values in swift enumerations

扶醉桌前 提交于 2019-12-03 12:00:27

Raw values are for when every case in the enumeration is represented by a compile-time-set value. The are akin to constants, i.e.

let A = 0
let B = 1

is similar to:

enum E: Int {
    case A  // if you don't specify, IntegerLiteralConvertible-based enums start at 0
    case B
}

So, A has a fixed raw value of 0, B of 1 etc set at compile time. They all have to be the same type (the type of the raw value is for the whole enum, not each individual case). They can only be literal-convertible strings, characters or numbers. And they all have to be distinct (no two enums can have the same raw value).

Associated values are more like variables, associated with one of the enumeration cases:

enum E {
    case A(Int)
    case B
    case C(String)
}

Here, A now has an associated Int that can hold any integer value. B on the other hand, has no associated value. And C has an associated String. Associated types can be of any type, not just strings or numbers.

Any given value of type E will only ever hold one of the associated types, i.e. either an Int if the enum is an A, or a String if the enum is a C. It only needs enough space for the bigger of the two. Types like this are sometimes referred to as "discriminated unions" – a union being a variable that can hold multiple different types, but you know (from the enum case) which one it is holding.

They can even be generic. The most common example of which is Optional, which is defined like this:

enum Optional<T> {
    case .Some(T)
    case .None
}

Answers by @Airspeed Velocity and @yoAlex5 explain the difference well, but they state than

enums can have either associated either raw values.

This is not so for Swift 4 and 5. Here is a good illustration on for having them both in one enum. You'll need default values for raw value initialiser, of course.

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