Interrupting blocked read

问题

My program goes through a loop like this:

...
while(1){
  read(sockfd,buf,sizeof(buf));
  ...
}

The read function blocks when it is waiting for input, which happens to be from a socket. I want to handle SIGINT and basically tell it to stop the read function if it is reading and then call an arbitrary function. What is the best way to do this?

回答1:

From read(2):

   EINTR  The call was interrupted by a signal before any data
          was read; see signal(7).

If you amend your code to look more like:

cont = 1;
while (1 && cont) {
    ret = read(sockfd, buf, sizeof(buf));
    if (ret < 0 && errno == EINTR)
        cont = arbitrary_function();
}

This lets arbitrary_function() decide if the read(2) should be re-tried or not.

Update

You need to handle the signal in order to get the EINTR behavior from read(2):

#include<unistd.h>
#include<stdio.h>
#include<stdlib.h>
#include<signal.h>
#include<errno.h>

int interrupted;

void handle_int(num) {
  interrupted = 1;
}

int main(void){
  char buf[9001];
  struct sigaction int_handler = {.sa_handler=handle_int};
  sigaction(SIGINT,&int_handler,0);
  while(!interrupted){
    printf("interrupted: %d\n", interrupted);
    if(read(0,buf,sizeof(buf))<0){
      if(errno==EINTR){
        puts("eintr");
      }else{
        printf("%d\n",errno);
      }
      puts(".");
    }
  }
  puts("end");
  return 0;
}

Gives output:

$ ./foo
interrupted: 0
hello
interrupted: 0
^Ceintr
.
end

回答2:

When your process receives a signal, read() will return and the value of errno will be set to EINTR.

来源：https://stackoverflow.com/questions/6249577/interrupting-blocked-read

标签

Linux

signals

interrupt