How does “+var === +var” work internally to verify if var is numeric?

北城余情 提交于 2019-12-03 09:18:24

+ converts the value to a number.

a gets converted to 123 and 123 === 123.

b gets converted to NaN but NaN !== NaN (because NaN is never equal to another NaN according step 4a of the equality rules).

The + operator here is known as the Unary Plus.

The unary plus operator precedes its operand and evaluates to its operand but attempts to converts it into a number, if it isn't already.

+"123" evaulates as 123.

+a === +a
-> +"123" === +"123"
  -> 123 === 123
    -> true

+"123b" evaluates as NaN (Not a Number), as the b character cannot be converted with the Unary Plus as without any prefix (like 0x for hexadecimal) the Unary Plus will assume the value is decimal (0-9). NaN is a special case in that it does not compare against anything, including itself:

NaN === NaN
-> false

NaN !== NaN
-> true

Because of this, our +b test case fails:

+b === +b
-> +"123b" === +"123b"
  -> NaN === NaN
    -> false

If you want both to evaluate to true we can add an isNaN() call at the end:

if ( +a === +a || isNaN(+a) )

if ( +b === +b || isNaN(+b) )

The two variables are string, but javascript convert automatically any string to a number when you + or - .

var a = "1";
var b = a;     // b = "1": a string
var c = +a;    // c = 1: a number
var d = -a;    // d = -1: a number

and Basically in your example you try to do this:

if ( +"123" === +"123" )  => ( 123 === 123) // true
if ( +"123b" === +"123b" ) => (NaN === NaN) // false
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