How do you create pretty json in CHEF (ruby)

倾然丶 夕夏残阳落幕 提交于 2019-12-03 07:37:29
spuder

As pointed out by this SO Answer .erb templates are great for HTML, and XML, but is not good for json.

Luckily, CHEF uses its own json library which has support for this using .to_json_pretty

@coderanger in IRC, pointed out that you can use this library right inside the recipe. This article shows more extensively how to use chef helpers in recipes.

default.rb

# if ['foo']['bar'] is null, to_json_pretty() will error
default['foo']['bar'] = {}

recipe/foo.rb

pretty_settings = Chef::JSONCompat.to_json_pretty(node['foo']['bar'])

template "foo.json" do
  source 'foo.json.erb'
  variables :settings => pretty_settings
  action :create
end

Or more concise as pointed out by YMMV

default.rb

# if ['foo']['bar'] is null, to_json_pretty() will error
default['foo']['bar'] = {}

recipe/foo.rb

template "foo.json" do
  source 'foo.json.erb'
  variables :settings => node['foo']['bar']
  action :create
end

templates/foo.json.erb

<%= Chef::JSONCompat.to_json_pretty(@settings) %>

Something like this would also work:

file "/var/my-file.json" do
  content Chef::JSONCompat.to_json_pretty(node['foo']['bar'].to_hash)
end
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